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What is the Lebesgue covering dimension of this topological space?

Concerning the Lebesgue covering dimension, absolutely nothing can be said, if you work with manifolds of total space-time dimension 3 or higher. Preamble We will consider spacetimes with closed ...
Willie Wong's user avatar
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Dimension of Alexandrov space which is homeomorphic to a manifold

If $n$ is defined, then the statement has already been proved in the paper by Burago, Gromov, and Perelman. However, there might be no such $n$; in other words, the space has infinite dimension in ...
Anton Petrunin's user avatar

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