New answers tagged

12 votes
Accepted

Closed form for ₄F₃(n,n,n,2n;1+n,1+n,1+n;−1)

Fiddling with Maple, I get: if $n$ is a positive real number, then $$ {{_4\mathrm F_3}(n,n,n,2\,n;\,n+1,n+1,n+1;\,-1)}={\frac {{n}^{2} \sqrt {\pi}\,\Gamma(n+1)\,\psi^{(1)}(n)}{{4}^{n}\,\Gamma \left( n ...

Top 50 recent answers are included