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22 votes
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reference for: no finite set of positive (integer) binary quadratic forms represents all primes

This is indeed correct; I don't know a reference, but here's a proof. Let ${\mathcal D}$ be a finite set of $K$ negative fundamental discriminants. We want to show that the set of primes not ...
Lucia's user avatar
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21 votes
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Is the diophantine equation $3x^2+1=py^2$ always solvable for each prime $p\equiv 13\pmod{24}$?

Updated on 2019/08/21: I prove Conjectures 1-3 below. I will use the usual terminology and notations for binary quadratic forms. In particular, I will use the first two pages of Pall: Discriminantal ...
GH from MO's user avatar
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18 votes
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Infinite cyclic subgroups of $\text{SL}_2(\mathbb{Z})$

The maximal infinite cyclic subgroups are of the form you mentioned (to get all infinite cyclic subgroups you also need to include their finite index subgroups). This follows from Theorem 1.4 in ...
Alison Miller's user avatar
16 votes

$x^2+7y^2=2^n$ and sums of four squares

The Diophantine equation $x^2 + 7y^2 = 2^n$ is "trivial" in the sense that its solutions can be described in a very simple way (see boxed formula near the end for solutions in odd numbers ...
KConrad's user avatar
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16 votes
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Primes of the form $x^2 + y^2 + 1$

Iwaniec (Acta Arith. 1972) showed that the number of such primes has the order $x/(\log x)^{3/2}$. His result applies more generally to translates of binary quadratic forms. One can also show that ...
Lucia's user avatar
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11 votes
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Equidistribution of CM points in the principal genus

This is known, and follows from Theorem 2 in Harcos and Michel's paper The subconvexity problem for Rankin-Selberg $L$-functions and equidistribution of Heegner points. II (Invent. math., vol. 163, ...
Vesselin Dimitrov's user avatar
11 votes
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A conjecture for primes $p\equiv\pm1\pmod5$

Let us consider $\mathbb{Q}(\sqrt{5})$ as a subfield of $\mathbb{R}$. Let us also consider the positive fundamental unit $\epsilon:=(1+\sqrt{5})/2$, whose square generates the group of totally ...
GH from MO's user avatar
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11 votes
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Could efficient solutions of $x^2+n y^2=A$ be related to integer factorization?

Short answer: no, what you propose does not work. A related method does work, and is already well-known. Full answer: Since the goal is factorisation, let us assume $n$ has no small prime factors and $...
Aurel's user avatar
  • 5,382
10 votes

Equidistribution of CM points in the principal genus

Vesselin Dimitrov gave a nice answer, but let me point out that for the OP's question one does not need the result of Harcos-Michel (2006). Instead, the original work of Duke (1988) or alternatively ...
GH from MO's user avatar
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10 votes
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The mean value of $y \log{y}$ over the ordinates of the CM points

Let $g : \Gamma \backslash \mathbb{H} \to \mathbb{C}$ be any bounded continuous function. Duke's theorem states that \[\frac{1}{h(D)} \sum_{A \in \mathrm{Cl}_K} g(z_A) = \frac{1}{\mathrm{vol}(\Gamma \...
Peter Humphries's user avatar
9 votes

Equivalence of binary quadratic forms over $\operatorname{GL}_2(\mathbb{Q}_p)$ or $\operatorname{GL}_2(\mathbb{Z}_p)$

The number of classes of (regular) binary quadratic forms over $\mathbb{Q}_p$ equals $7$ when $p\neq 2$, and it equals $15$ if $p=2$. See Section IV.2.3 of Serre: A course in arithmetic. The number ...
GH from MO's user avatar
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8 votes
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Representation of integers by principal binary quadratic forms

There are precisely two such proper divisors of $k$, and their product equals $-k$. This result is essentially due to Gauss, see Theorem 1 in Pall: Discriminantal divisors of binary quadratic forms, J....
GH from MO's user avatar
  • 105k
8 votes
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Representation of two related integers by the same binary quadratic form

This question can be answered by general theory, at least when $\Delta$ is a fundamental discriminant (so it's not a square times a smaller discriminant). Assuming this, the general procedure for ...
Allen Hatcher's user avatar
8 votes
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On binary quadratic forms which are not proper subforms of another binary quadratic form

Yes. It is about equivalence over $SL_2 \mathbb Z.$ Your form $f$ (primitively) represents some value not divisible by the fixed prime $p.$ Indeed, from original coefficients $\langle a,b,c \rangle$ ...
Will Jagy's user avatar
  • 25.7k
8 votes

asymptotics of numbers represented by certain indefinite binary quadratic forms

This follows from Bernays' generalization of Landau's theorem, the original reference is this: P. Bernays, Uber die Darstellung von positiven, ganzen Zahlen durch die primitiven, binaren ...
Stanley Yao Xiao's user avatar
7 votes

The mean value of $y \log{y}$ over the ordinates of the CM points

Can we do this by reducing it to a sum over ideals? By Duke's theorem, we can easily deal with the low $y$ terms. Thus we can adjust the boundary condition to $-a < b \leq a < \sqrt{- D /3 }$. ...
Will Sawin's user avatar
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6 votes
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heights of ideal classes and reduction theory for Bhargava cubes

No, it is not true that $M(D) = o(|D|^{3/2})$. For example, if $D = -4abcd$ where $a,b,c,d$ are odd, pairwise coprime and of roughly equal size, then the forms $ab\,x^2+cd\,y^2, ac\,x^2+bd\,y^2, ad\,...
Noam D. Elkies's user avatar
5 votes
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A class number estimate

This is from Buell, Binary Quadratic Forms, pages 109-119. Note that $h(-16) = h(-4) = 1.$ When $p$ is an odd prime, we use the Legndre symbol in $$ h(-4p^2) = \frac{p - (-1|p)}{2} $$ After that, ...
Will Jagy's user avatar
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5 votes
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Representing positive integers $n$ by binary forms $n=ax^2+by^2$, $a\geq 0$, $b\geq 0$

There is no such finite set of pairs $(a_k,b_k)\in\mathbb{Q}_{\geq 0}^2$. Indeed, because the problem concerns rational representations, we can assume without loss of generality that $(a_k,b_k)\in\...
GH from MO's user avatar
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4 votes

Is the diophantine equation $3x^2+1=py^2$ always solvable for each prime $p\equiv 13\pmod{24}$?

Here's a second proof of Claim 1 (I guess the others can be taken care of similarly) that perhaps explains a little bit better what is going on. Assume first that $3x^2 + 1 = py^2$ has an integral ...
Franz Lemmermeyer's user avatar
4 votes

On the equivalence of a pair of binary quadratic forms

The exact class number formula was given by Jorge Morales in the following paper: Jorge Morales. The classification of pairs of binary quadratic forms. Acta Arith., 59(2):105–121, 1991. In ...
Stanley Yao Xiao's user avatar
4 votes

On the equivalence of a pair of binary quadratic forms

We can show that $ h(1,1,n) $ increases like $ n $-th powers of 2 : indeed, in the half-plane presentation of the set of positive definite quadratic forms, the euclidean form is identified to $ ...
few_reps's user avatar
  • 1,980
4 votes
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Ray class groups through binary quadratic forms

I guess that the answer is no. The binary forms with discriminant $\Delta \cdot f^2$ describe ring class fields modulo $f$ (see Cox's book), so by taking the limit as $f \to \infty$ something like ...
Franz Lemmermeyer's user avatar
4 votes

On the notion of primary representation of a natural number by a quadratic form

I'm going to take a more algebraic number theoretic approach to this question. The solutions to $x^2-dy^2=k$ are the integers of norm $k$ in the number field $\mathbb{Z}[\sqrt(d)]$ if $d$ is a ...
Watson Ladd's user avatar
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4 votes

Is the set of integers represented by a quadratic form of non-fundamental discriminant a subset of the rep. set of a form of fundamental discriminant?

This is true, of course. The book you want is Binary Quadratic Forms by D. A. Buell. He talks about how, given some discriminant $\Delta$ and class number(primitive forms) $h(\Delta),$ we can predict $...
Will Jagy's user avatar
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4 votes
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Solvability of two-variable quadratic equations with a parameter

Both equations are solvable in integers $(x,y)$ for infinitely many values of $a$. Specifically, the first equation is solvable for every $a$ of the form $a=-(2^n+3)$ for integer $n$, while the second ...
Bogdan Grechuk's user avatar
4 votes
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A cubic equation, and integers of the form $a^2+32b^2$

Update 2. Now the proof should be more readable. I deleted some content because it is replaced by more elegant version. The equation is unsolvable. The proof requires two theorems Theorem 1. Let $p = ...
Denis Shatrov's user avatar
4 votes

On an integer factoring algorithm based on smooth class number of quadratic fields

This idea was first studied by Shanks, Pollard, Atkin and Rickert, although they didn't write a paper as far as I know. Schnorr and Lenstra gave a heuristic time complexity analysis in their 1987 ...
duckstar's user avatar
  • 191
3 votes
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Distribution of 'square classes' of binary quadratic forms

The standard definition for a form to belong to the principal genus of forms with fundamental discriminant $d$ is that the primes $p$ coprime to $d$ that the form $Q$ represents satisfy $(d_1/p) = \...
Franz Lemmermeyer's user avatar
3 votes

Classifying binary quadratic forms by the set of representable squares

No, the set $S_f$ is empty for lots of forms. For example, if $a$ is not a square modulo $b$, then $ax^2+by^2$ is never a square (consider the equation modulo $b$). Thus, $S_f$ is empty for $f(x,y)=6x^...
Alex B.'s user avatar
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