New answers tagged alexandrov-geometry
0
votes
Unbounded curvature implies infinite diameter on complete metric spaces
If you want something smoother, you can try an example like the surface in $\mathbb{R}^3$ given in spherical coordinates by $\rho=\text{exp}(-\theta)$ for $\theta \ge 0$. This kind of looks like a ...
8
votes
Amalgamated product acting on CAT(0) cube complex
To extend the gluing result from Bridson--Haefliger to non-positively curved cube complexes, it is important to work in the correct category.
If we want the result to also be a non-positively curved ...
3
votes
Amalgamated product acting on CAT(0) cube complex
I assume that isomorphic embedding really meant isometric embedding in the assumptions and thus $Y$ is really a convex subset of $X_i$ for all $i$.
Then the CAT(0)-space on which the amalgamated ...
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