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22 votes

Monoidal categories whose tensor has a left adjoint

If $\otimes : V \times V \to V$ has a left adjoint and $V$ has finite products then $\otimes$ preserves them in the sense that the natural map $$(X \times Y) \otimes (Z \times W) \to (X \otimes Z) \...
Qiaochu Yuan's user avatar
20 votes
Accepted

Surmounting set-theoretical difficulties in algebraic geometry

Let me start by discussing a bit the option of having a large class of generators. You might be interested in the notion of locally class-presentable. To be precise here, I need to be a bit set-...
Ivan Di Liberti's user avatar
20 votes
Accepted

Monoidal categories whose tensor has a left adjoint

Just to clean up the $\epsilon$ of room left after Qiaochu's answer -- we can get rid of the extra hypotheses. I'll write $I$ for the monoidal unit and $1$ for the terminal object. Assume that $(\ell,...
Tim Campion's user avatar
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19 votes
Accepted

Notation for "the" left adjoint functor

In EGA 0.1.5.2-3 (from the 1971 Springer edition) the right adjoint and the left adjoint of a functor $F$ are denoted by $F^{\rm ad}$ and ${}^{\rm ad}\!F$, respectively.
Fred Rohrer's user avatar
  • 6,710
19 votes

Reference request: Who first proved that right adjoints preserve limits?

Daniel M. Kan defined adjoint functors in his paper Adjoint functors (written in 1956). In Chapter II he defines limits and colimits of arbitrary small diagrams and proves that the limit and colimit ...
Dmitri Pavlov's user avatar
17 votes
Accepted

Minimal set of assumptions for set theory in order to do basic category theory

To complement Tom Leinster's answer, let me try to be specific: To form the product category $\mathcal{C} \times \mathcal{D}$, we need ordered pairs, which we can get from the axiom of unordered ...
Andrej Bauer's user avatar
  • 48.9k
16 votes
Accepted

Is this space the Stone–Čech compactification?

No, the closure of the image of $f$ in $Y$ is never the Stone-Čech compactification of $X$ unless $X$ is empty. In particular, consider the element $a\in Y$ which is $1$ on every coordinate. Note ...
Eric Wofsey's user avatar
  • 31.2k
15 votes
Accepted

Can the category of S-local objects be reflective but not a localization by S?

Not in general, no - there must be some additional conditions on $S$, such as a saturation condition. Consider for instance the presentable case. Then if $S$ is small, $Loc(S) $ is always reflexive, ...
Maxime Ramzi's user avatar
  • 16.6k
14 votes
Accepted

Upgrade adjunction to equivalence

Let $\mathcal C$ and $\mathcal D$ be two categories, and let $F\colon\mathcal C\longrightarrow \mathcal D$ and $G\colon\mathcal D\longrightarrow\mathcal C$ be two functors, with $F$ left adjoint to $G$...
Leonid Positselski's user avatar
13 votes
Accepted

Explicit expression of the unstraightening functor

Wow, I have always thought that unstraightening has to be easier than straightening, but I've never actually looked at Lurie's treatment before, so I'm surprised to realize he defines straightening ...
Tim Campion's user avatar
  • 64.2k
13 votes

Upgrade adjunction to equivalence

Another and probably more natural interpretation of the sentence in the Wikipedia article may be called "localizing an adjunction to an equivalence". Let $\mathcal C$ and $\mathcal D$ be two ...
Leonid Positselski's user avatar
13 votes

Minimal set of assumptions for set theory in order to do basic category theory

You ask what assumptions on sets are needed in a "normal first course on category theory". There are several possible kinds of answer, and this is an answer of the practical kind, i.e. from ...
Tom Leinster's user avatar
  • 27.8k
12 votes

A specific property of bi-adjunction

(This is not an answer to your question, just a long comment.) There is something to be careful about with ambidextrous adjunctions. When we work with an ordinary adjunction we can rest assured that ...
Qiaochu Yuan's user avatar
11 votes
Accepted

Reference request: The unit of an adjunction of $\infty$-categories in the sense of Riehl-Verity is a unit in the sense of Lurie

Let $\mathcal{C},\mathcal{D}$ two $\infty$-categories and $f:\mathcal{C}\to\mathcal{D}$ and $g:\mathcal{D}\to \mathcal{C}$ two functors. Recall (HTT.5.2.2.7) that a natural transformation $u:1_{\...
Denis Nardin's user avatar
  • 16.5k
11 votes
Accepted

Characterization of functors whose right adjoint is monadic?

Let $F: C \to D$ be a left adjoint functor. I hope I'm not saying anything stupid, but I think you can just rephrase the two conditions of Beck Monadicity theorem in terms of the left adjoint: The ...
Simon Henry's user avatar
  • 42.6k
11 votes

Prof and the completion of Cat under right adjoints

The idea that passing from $Cat$ to $Prof$ is a great way to give functors adjoints features prominently in Richard Wood's theory of proarrow equipments. Rosebrugh and Wood showed in Proarrows and ...
Tim Campion's user avatar
  • 64.2k
10 votes
Accepted

If a right adjoint to the product functor exists, must it be the diagonal?

For the first question: Yes. Let $C$ be a category with finite products and let $\Delta=(\Delta_1,\Delta_2):C\to C\times C$ s.t. $$\times\dashv \Delta.$$ More specifically we find $$[X\times Y, Z]\...
Gerrit Begher's user avatar
10 votes

Which direction of the adjoint functor theorem is most useful?

In 1-category theory, the easy direction (a) is invoked all the time. The hard direction (b) doesn't have to be formally invoked very often, because most adjoints can be constructed by hand (and even ...
Tim Campion's user avatar
  • 64.2k
9 votes

If a right adjoint to the product functor exists, must it be the diagonal?

Building on Garlef Wegart's work, the answer is yes in general. The idea is to show that if $C$ has a right adjoint to $\times$, then it is enriched in pointed sets, so that $C$ embeds fully ...
9 votes

Categories which are both monadic and comonadic over another category

I understand it like this: if a monad $M: C \to C$ has a right adjoint $K: C \to C$, then that right adjoint carries a comonad structure which is mated to the monad structure, and the category of $M$-...
Todd Trimble's user avatar
  • 53.4k
9 votes

Upgrade adjunction to equivalence

I think the author of the wikipedia article probably had in mind Leonid Positselski's first answer, where one restricts to the full subcategory of fixed points of the adjunction. Beware there is no ...
Tim Campion's user avatar
  • 64.2k
9 votes
Accepted

$\infty$-natural transformations and adjunctions

1- Your natural transformation can be seen as a functor $C \to D^{\Delta^1}$, which therefore induces a commutative square of $\infty$-categories $\require{AMScd} \begin{CD} C_{x/} @>>> D^{\...
Maxime Ramzi's user avatar
  • 16.6k
9 votes

Which functors preserve the number of connected components?

You don't give your definition of $\pi_0$ on $\text{Top}$, but since you mention left adjoints I assume it is the left adjoint of the inclusion $\text{Set} \to \text{Top}$ of discrete spaces into $\...
Qiaochu Yuan's user avatar
9 votes
Accepted

Which spectra have a universal connective quotient?

This answer is about the $\infty$-categorical variant. This is a fancy way to say: on spaces of maps, the natural map $$ Map(T',A) \to Map(T,A) $$ is an equivalence for any connective $A$. Note that ...
Tyler Lawson's user avatar
  • 52.9k
8 votes

Can adjoint linear transformations be naturally realized as adjoint functors?

Not exactly an answer to the question as posed, but it's worth noting that adjoint linear maps and adjoint functors can both be realized as instances of the same thing, namely morphisms in a Chu ...
Mike Shulman's user avatar
  • 67.1k
8 votes
Accepted

Adjoints of scalar extension and scalar coextension

If $X$ is an $R$-module, there is a natural map $M\otimes_RX\to\text{Hom}_R\left(\text{Hom}_R(X,R),M\right)$ given by $m\otimes x\mapsto[\varphi\mapsto m\varphi(x)]$ that is easily checked to be an ...
Jeremy Rickard's user avatar
8 votes

Adjunctions between Groupoids and Hilbert spaces

I don't know what morphisms you intend for the category of finite-dimensional Hilbert spaces, but it doesn't actually matter. The answer is no, there are no interesting adjunctions between the ...
Tim Campion's user avatar
  • 64.2k
8 votes

Adjoints for radical and socle functors

In abelian groups: $$\text{soc}\left(\prod_{p\text{ prime}} \mathbb{Z}/p\mathbb{Z}\right) = \bigoplus_{p\text{ prime}} \mathbb{Z}/p\mathbb{Z}\not\cong \prod_{p\text{ prime}}\mathbb{Z}/p\mathbb{Z} = \...
Alex Kruckman's user avatar
8 votes
Accepted

How to understand adjoint functors?

Nice question Bumblebee. So, let us start with some "metaphysics of adjointness": THE LEFT AND RIGHT ADJOINTS TO A FUNCTOR $ \mathcal{F}:\mathcal{C}\hookrightarrow\mathcal{D}$ ARE THE FREE (...
Mirco A. Mannucci's user avatar
8 votes

A specific property of bi-adjunction

Qiaochu Yuan’s answer excellently explains the general phenomenon. Here is another slightly simpler concrete example: Let $\newcommand{\Z}{\mathbb{Z}}\newcommand{\BZ}{{\mathbf{B}\Z}}\BZ$ be the group ...
Peter LeFanu Lumsdaine's user avatar

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