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What is the role of equivariance in the Atiyah-Singer index theorem?

This procedure involves a bit of equivariant considerations, but no equivariant $K$-theory. … Why do Atiyah and Singer need equivariant $K$-theory? The question is why they need $K (\mathbb{R}^n)$, equivariant or nonequivariant, at all. …
Johannes Ebert's user avatar
10 votes

Equivariant homology of $\Omega X$\/-space (references needed)?

Preferring simple answers, equivariant homology means Borel-equivariant homology, i.e. homology of the Borel construction. But what is $E \Omega X \times_{\Omega X} Y$? … So the Borel construction is $E$ and it follows: ''The $\Omega X$-Borel-equivariant homology of $Y$ is the homology of $E$.'' …
Johannes Ebert's user avatar