Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 91341

Dynamics of flows and maps (continuous and discrete time), including infinite-dimensional dynamics, Hamiltonian dynamics, ergodic theory.

0 votes

Identification of Invariant Sets for Discrete Dynamical Systems on the Positive Integers

This is a fairly substantial rewriting of my original answer. Sharkovski's theorem, which unfortunately only applies to $\mathbb{R}$ is the definitive theorem in this field and one thing it states is …
Robert Frost's user avatar
2 votes

A Collatz-like function that bifurcates on primes

The full detail of this is of course a complex matter but I can build out some structure and connect the problem to some powerful tools for you; namely that, like the Collatz conjecture, this structur …
Robert Frost's user avatar
-1 votes
1 answer
299 views

Is this submonoid of the isometry group on $\Bbb Q_2$ closed to inverses? [closed]

Let $\textrm{aff}(ax+b)$ be the affine group on $\Bbb Z_2^\times$ i.e. the set of linear polynomials over 2-adic numbers with $a\in\Bbb Z_2^\times, b\in\Bbb Z_2$ Now let $X$ be the restriction of its …
Robert Frost's user avatar
1 vote
Accepted

Finding a two point scrambled set for the function $g:[0,1] \rightarrow [0,1], x \mapsto \mi...

Having digested your definitions... Any number which has an aperiodic orbit (not a fixed point), and any number which has a periodic orbit (possibly a fixed point), will between them constitute a two- …
Robert Frost's user avatar
1 vote

Dropping three bodies

I believe your first proof is trivial since any 3 points may always be placed on a plane and since their gravity will attract along the plane they will remain on it in perpetuity. Then any 2 points sa …
Robert Frost's user avatar