Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with higher-category-theory
Search options not deleted
user 90758
For questions involving one or more categorical dimensions, or involving homotopy coherent categorical structures.
0
votes
Set of functions is not a bifunctor on Rel
Assuming that the second f is supposed to be g, notice that functions are also relations. So, f is related to g iff the square $$ \begin{array}{ccc}
X & \stackrel{R}{\to} & X' \\ f \d …
- 218