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Euclidean, hyperbolic, discrete, convex, coarse geometry, metric spaces, comparisons in Riemannian geometry, symmetric spaces.
6
votes
2
answers
410
views
What is the geometric meaning of one Riemannian metric bigger than the other one on a smooth...
Gromov conjectured in 1985 and LLarull proved in 1998 that: If $g > g_0$ on the sphere, then there exists some point p on the sphere with $Sc(p) < Sc_0(p)$. Here $g, g_0$ are Riemannian metrics and $g …
1
vote
What is the geometric meaning of one Riemannian metric bigger than the other one on a smooth...
Lohkamp Scalar curvature and hammocks proved that it it always possible to decrease both the metric and the scalar curvature simultaneously, as pointes out by Goette and Semmelmann in the paper Scala …
1
vote
0
answers
323
views
What is the meaning of Conjugate radius and Injectivity radius?
I review the text book of differential geometry and I find that the conjugate radius and injectivity radius are still enigmatic for me. Here is a quetion which I confuse it. I don't think it is true, …
5
votes
1
answer
247
views
If M times circle admits a locally CAT(0)-metric, then M also carries a locally CAT(0)-metric?
A locally CAT(0) metric on length space means that every point in it has a geodesically convex neighborhood such that every triangle in it is slimmer than the comparison triangle in the Euclidean plan …
5
votes
3
answers
355
views
Recovering the length metric from Hausdorff measure
The metric cannot be recovered from its Hausdorff measure in general. Now, assume that $(X,d_X)$ and $(Y, d_Y)$ are connected compact length spaces and induce $n$-dimensional Hausdorff measures $\mat …
3
votes
0
answers
92
views
What can be reflected by the $C^0$-limit of Riemannian metrics?
Let $M^n$ be a closed connected smooth manifold and {$g_i$} be a family of smooth Riemannian metrics on it such that $g_i$ $C^0$-converges to the smooth Riemannian metric $g$ on $M^n$.
Can it possi …
7
votes
1
answer
257
views
Can we realize the smooth metric of an Alexandrov space with nonnegative curvature by a Riem...
We know that a smooth Riemannian manifold with nonnegative curvature is an Alexandrov space (with induced metric) of nonnegative curvature.
What about the converse? That is, given a smooth metric d o …