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For questions about matchings in graph theory. A matching on a graph is a set of edges such that no two edges share a common vertex.

9 votes
Accepted

Graphs with unique 1-Factorization

If there is only one edge colouring with $k$ colours of a graph with chromatic index $k$, the graph is said to be "uniquely edge colourable". If you search on that phrase (with and without the second …
Brendan McKay's user avatar
6 votes
Accepted

Does there exist an r-regular graph (r≥2) with a unique maximum matching?

Take a maximum matching $M$ and a vertex $v$ not in $M$. If $v$ has a neighbour $w$ not in $M$, then $M+vw$ is a larger matching. So $v$ has a neighbour $x$ which is in an edge $xy$ of $M$. Now $M-x …
Brendan McKay's user avatar
4 votes
Accepted

Interpreting optimal matchings as permutations

$$\pmatrix{ 2&3&0&0\\0&2&3&0\\0&0&2&3\\3&0&0&2}$$ Every swap of two columns or swap of two rows decreases the trace. However, there is a permutation putting all the 3s on the diagonal.
Brendan McKay's user avatar
5 votes

Unique matching completion

Take a circular ladder of odd length. Also known as the cartesian product of $C_n$ ($n$ odd) and $K_2$. For every perfect matching there are many ways to change it into a different perfect matching by …
Brendan McKay's user avatar
9 votes
Accepted

Roots of matching polynomial of graph

The moments (power symmetric functions, sums of powers of the roots of) the characteristic polynomial enumerate all closed walks in the graph. Chris Godsil proved that the moments of the matching pol …
Brendan McKay's user avatar
4 votes

Matching polynomials and Ramanujan graphs

The moments of the adjacency matrix eigenvalues count closed walks in the graph, while the moments of the matching polynomial roots count tree-like closed walks. When the graph has few short cycles, a …
Brendan McKay's user avatar
1 vote
Accepted

Counting matchings in a bipartite matching-covered graph

Yes, it is still just as hard. Given an arbitrary bipartite graph, in polynomial time you can remove every edge that is not in a perfect matching (test one edge at a time), thus reducing the problem …
Brendan McKay's user avatar