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for questions involving inequalities, upper and lower bounds.
5
votes
An inequality improvement on AMM 11145
An extended comment that has a chance of being useful.
First, note that if you interchange $a_k$ and $a_{k+1}$ then only the $k$-th term on the left side changes and the right side doesn't change at …
1
vote
An inequality about the sum of some unit fractions with a property
This is not an answer, but I want to use displays. What you are asking is whether the coefficients of the taylor expansion of
$$\left( \sum_{k=0}^\infty \frac{x^k}{(N-1)k+1} \right)^N$$
are all at mo …
6
votes
Find the maximum of the value $c(n)$ (similar to Hardy's inequality)
On the basis of rather convincing numerical evidence (iterative optimisation that always converges to the same place regardless of starting point), I conjecture that the worst case is
$$ a_i = \frac{i …
10
votes
Accepted
Want to prove an inequality
Iosif's answer is very interesting and if anyone knows how to do the same thing in Maple I'd like to know.
However I disagree with Iosif about the difficulty. Mathematica will use a systematic proced …
1
vote
Two-Sided Bounds on Binomial Sum
If you want a more precise value you can expand $k^{-s}$ around $k=N/2$ and sum term by term. I get
$$\frac{2^N}{(N/2)^s}\Bigl(1 + \frac{s(1+s)}{2N} +
\frac{s(1+s)(2+s)(3+s)}{8N^2} + O(N^{-3})\Bigr). …
8
votes
Accepted
Sum over integer compositions
Since the question is about compositions, there is a generating function approach when $\phi(a_1,\ldots,a_n)=\prod_i f(a_1)$ for some function $f$. Namely, $S(n,k)$ is the coefficient of $x^n$ in $\l …
1
vote
Accepted
For which $p>p^*$ does the inequality $\cos^2(−π/4+π/p)>1/2+π/p^2$ hold?
Sketch:
Write $p=1/x$, so that you want to show
$f(x) = \sin(\pi/4+\pi x)-1/2-\pi x^2\ge 0$ for $0\le x\le 0.355$ approximately.
First, $f''(x)<0$ in $[0,1/2]$ (by a large margin), so $f'(x)$ is stric …
3
votes
Variance of truncated normal distribution
This paper is relevant:
E. Mailhot, Une propriété de la variance de certaines lois de probabilité réelles tronqées, C. R. Acad. Sci. Paris Sér. I Math. 301 (1985) 241–244.
Mailhot proves that the va …
0
votes
Power function inequality
Since the case $x=1$ is trivial, assume $x>1$ and divide both sides by $x-1$. It becomes
$$(x+1)^{p-1}\ge \frac{x^p-1}{x-1} = 1 + x + x^2 + \cdots + x^{p-1}.$$
Expand the left side by the binomial the …
3
votes
1
answer
152
views
Bounds on symmetric polynomials in power-sum form with bounded coefficients
Let $\boldsymbol{x}=(x_1,\ldots,x_n)$ be a real vector. Define the normalized power-sum symmetric polynomials by $\pi_j(\boldsymbol{x})=\frac 1n(x_1^j+\cdots+x_n^j)$.
For a partition $\lambda= (j_1,\l …
3
votes
An inequality involving binomial coefficients and the powers of two
If the value of the sum is $\frac13-\varDelta(k)$, then it appears that $\varDelta(k)$ satisfies the recurrence
$$ (8k+4)\varDelta(k) = (7k-5)\varDelta(k-1) + k\varDelta(k-2).$$
Note that I didn't pro …
0
votes
The exact constant in a bound on ratios of Gamma functions
Taking $f(a,b)=\frac{a+b}{a}$ as in the other question, I conjecture that the optimal $C$ is $e$.
One bit of evidence is that the limit of the ratio for $a=cb$ and $b\to\infty$ is $(c+1)^{1/c}$ which …