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Asymptotic behavior of functions, asymptotic series and related topics

4 votes

Asymptotics of a recurrence relation

I get a slightly different answer every time I look at it, so I hope the following is ok. I won't dot every last "i" in the error analysis. Let $F(t)=\sum_{i=0}^\infty a_i(t)$, where $a_i(t)=t^{2^i}2 …
Brendan McKay's user avatar
6 votes
Accepted

Asymptotic expression for $j$ which satisfies $\binom{n}{j}/j! \sim k$ as $n\to\infty$

(CORRECTED EDITION) By mucking around with expansions like Igor suggested, I found $$ j \approx J(n,k)= en^{1/2} - \tfrac14\ln(n) -\tfrac12\ln(2\pi k)-\tfrac14 e^2-\tfrac12. $$ It seems good when …
Brendan McKay's user avatar
3 votes

Finding the asymptotic bound of a summation

(Edited after Christian's comments.) For $0\le i\le n^{4/7}$, $$n!/(n-i)! = n^i \exp(-i(i-1)/(2n)+O(i^3/n^2)).$$ Approximate the sum for that range by the corresponding integral (a gaussian with the …
Brendan McKay's user avatar
3 votes
Accepted

Is there an asymptotic formula for an inverse function of the binomial coefficient?

The approximation coming from the normal approximation of the binomial distribution is $$ k = \sqrt{-2n\ln(1-\epsilon)}.$$ To get more terms write $\Delta=-\ln(1-\epsilon)$, then by expanding $-\ln(1- …
Brendan McKay's user avatar
2 votes

Multinomial Coefficient Estimates

There is a chapter in Knuth and Greene, Mathematics for the analysis of algorithms, that explains how to estimate this type of thing. If $B$ is fixed and $n\to\infty$, the central limit theorem might …
Brendan McKay's user avatar
0 votes

Asymptotics of repeated decrease by logarithmic part

I'm guessing you can approximate it with the differential equation $$ x'(n) = -\log(x(n)). $$ The solution to this satisfies some equation involving the exponential integral special function, namely $ …
Brendan McKay's user avatar
2 votes

Asymptotics for the sums from the inclusion-exclusion principle

Many unsolved asymptotics problems can be written as inclusion-exclusion sums. There is no general method for solving them. …
Brendan McKay's user avatar
6 votes

Asymptotics of functional of i.i.d. Rademacher random variables

EDITED: As pointed out by Anthony and John, my 2am solution was anything but. In summary, the conjecture is TRUE for $C$ smaller than approximately 0.6880137 and false for larger $C$. The exact value …
Brendan McKay's user avatar
2 votes

Asymptotics of the number of elements in the intersection of two growing sets

The problem statement exactly corresponds to the definition of the hypergeometric distribution. With this key-phrase in hand, it is easy to locate an extensive literature. Start with wikipedia for ba …
Brendan McKay's user avatar
7 votes
Accepted

The probability that two graphs have same number of edges

Since the vast majority graphs has trivial groups, and this is even more true (to exponential precision) for graphs with likely numbers of edges, the answer will be the same if you consider labelled g …
Brendan McKay's user avatar
0 votes

Asymptotics of the maximum of binomial random variables

I don't know where this is given in detail, but the method is the same as that used to obtain the distribution of the maximum degree of a random graph with $p=1/2$. In this range, the fact that the d …
Brendan McKay's user avatar
2 votes

Determining the asymptotic behavior of a series

Here is an elementary approach, which shows how to find the nature of $nf_n(t)$ as $n\to\infty$. But I'm not going to bound error terms or such so this remains an outline until those details are fill …
0 votes

Asymptotic bounds for a confluent hypergeometric function $F_{1}[;1;x]$

The OP is unclear about the domain of $z$ required. If only real $z\to\infty$ is of interest, just realise that the terms near $k=\sqrt z$ dominate the rest and their shape is close to a normal densi …
Brendan McKay's user avatar
8 votes
Accepted

Inverting an asymptotic series

Since you say that you only want the first few terms, one way you can do this type of thing is by making a contraction mapping. As $x\to\infty$, inspection shows $y\sim x$, so rewrite the equation as …
Brendan McKay's user avatar
5 votes

Limit of a Combinatorial Function

The limit is at least $2/\sqrt 3\approx 1.1547$. Write $\alpha=1/\sqrt 3$. If any strip length $\alpha n$ or more is used more than once, then obviously area $2\alpha$ can be chosen. On the other han …
Brendan McKay's user avatar

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