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Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.
7
votes
Selecting subsets with size $\frac{n}{2}$ covering every pair of the elements
If $n$ is a power of two (i.e. if $n=2^m$), you can do quite a bit better-- you can take $|T'|=O(\log(n))$.
Interpret the elements of $S$ as $m$-bit binary strings. Let $U_i^0$ be the set of element …
9
votes
Accepted
Solve system of logical equations
Let $A=a_0+a_1x+a_2x^2\cdots+a_nx^n$, $B=b_0+b_1x+\cdots+b_mx^m$, and $C=AB=c_0+\cdots+c_{n+m}x^{n+m}$, where arithmetic occurs over $\mathbb{F}_2$. Then your problem is exactly equivalent to recover …
35
votes
4
answers
2k
views
Graph containing all trees?
Consider graphs on $n$ nodes. I am trying to find a graph $G$ that contains all $n$-node trees as sub-graphs but contains as few edges as possible. The complete graph $K_n$ suffices, but can we get …
8
votes
0
answers
237
views
Size of 3-SAT assignments
Let $F(N,M)$ be the set of 3-SAT formula with $N$ variables and $M$ clauses. For a given formula $f\in F(N,M)$, we can ask for the set $s_f$ of truth assignments that satisfy $f$. (If $f$ is unsatis …
2
votes
Sequence A76132 eventually periodic modulo $2,3$ and $5$
The comment from "reuns" is the real answer-- the sequence is periodic for all $M$. For prime $M$, we can slightly improve the implied bound as follows.
We track the pair:
$$\left(j, \sum_{k=1}^{n}(a …
2
votes
What's the cumulative probability of these particular bags of liquorice allsorts?
I think the OP is re-inventing Fisher's Exact Test, so perhaps an examination of that may be clarifying.
FWIW, questions like this might be better suited to CrossValidated, which is a StackOverflow si …
1
vote
Unique naming/labeling of $40$-node strongly regular graphs
This may not be exactly what you had in mind, but in the context of displaying information on web pages, there is a need for a canonical labelling of graph isomorphism classes.
The proposed web standa …
6
votes
Bounds for the difference in the number of ones in $M$ and $M^{-1}$
This is a little numerical experiment, not an answer, but it provides a hypothesis for the shape of a solution. We (computationally) confirmed that matrices with this form have a discrepancy of $(n-2) …
12
votes
2
answers
589
views
Faster multiplication with a restricted set of multiplicands?
Let $A$ be a set of $k>1$ distinct elements from a semigroup. We wish to compute the product
$$ p=b_1 b_2 \cdots b_n$$
where each $b_i\in A$.
Clearly $n-1$ multiplications suffice to compute $p$; can …
12
votes
1
answer
864
views
The dance marathon problem
In his book, "The Strange Logic of Random Graphs", Joel Spencer describes the "Dance Marathon" problem:
Imagine $n$ couples at a Dance Marathon. Each dance each couple remains standing with independ …
2
votes
Graph alignment by considering node and edge weights
This is a very interesting problem, although I'm not sure if it's a mathematical problem exactly (as opposed to one of algorithmic modeling). That said, here are some two suggestions.
Suggestion #1: …
0
votes
Factoring a positive semidefinite matrix into binary matrices
This is more of a comment, but:
Depending on exactly how we define the family of sparse matrices, it may not be possible to recover a unique solution. In the example in the original post, the covari …
5
votes
(Non)uniqueness of the common-factor graph
A small change to Tony Huynh's proof gives a reasonably efficient algorithm for Q2.
Label the nodes as 1 through $k$. Select $2k$ distinct primes, listed as $p_1,...,p_k$ and $q_1,...,q_k$.
Let $s_ …
3
votes
1
answer
229
views
Counting cycle vertex covers on hypercube
Let $Q_n$ be the $n$-dimensional hypercube graph. How many vertex cycle covers exist on $Q_n$? (Presumably the best we can hope for are upper and lower bounds.) To be clear, a single "vertex cycle …
6
votes
Convergence speed of a random dyadic rational generator
This isn't an answer; I'm just sharing plots from a few numerical experiments. Each time we repeat the above process for $N$ steps, we generate a (potentially) different multiset (i.e., a different s …