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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.
2
votes
1
answer
224
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Global section of differential operators on moduli stack of G bundles
I know the definition of the ring of differential operators, by using the smooth coverings. But I do not know how to calculate the global section.
Can anyone help explain that why the global section …
1
vote
Global section of differential operators on moduli stack of G bundles
A naive way to see why we need twist by square root of $\omega_{S}$ is the following.
Given $L:\omega_{S}^{1/2}\rightarrow \omega_{S}^{1/2}$, we can form its adjoint $L^{t}:\omega_{S}^{1/2}\rightarrow …
4
votes
0
answers
105
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Construction of intersection forms for semismall maps
I am reading De Cataldo and Migliorini's beautiful paper "the hard Lefschetz theorem and the topology of semismall maps", where they construct an intersection form for each relevant strata, and whose …
4
votes
1
answer
573
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kahler differential on hyperelliptic curves
Suppose $X$ is a projective smooth, geometrically connected, hyperelliptic curves over a field k, we may ask $X(k)\neq\varnothing$. I want to know how to compute the $H^{0}(X,\Omega_{X}^{1})$.
And th …
2
votes
0
answers
184
views
Is the Lie algebra of a flat group scheme still flat?
Let $\mathcal{O}$ be a discrete valuation ring, and $\mathcal{G}$ is a flat group scheme over $\mathcal{O}$, we may assume the generic fiber is reductive. Then can we define its Lie algebra, and wheth …
0
votes
Connection between 'Separated scheme of finite type over spec(k)' and 'Curve in $\mathbb R^n$
I think when you mention a smooth map, the condition seems appear in the category of diffential geometry, which is quite different. The concept of 1 dimensional separated scheme (since we consider cur …
4
votes
0
answers
106
views
Is there Thom isomorphism for equivariant K groups in algebraic geometry, not necessarily co...
In Chriss and Ginzburg's fantastic book 'representation theory and complex geometry', they use the following Thom Isomorphism:
$\pi:E\rightarrow X$, is a G-equivariant affine linear bundle, then $\pi …