Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Theory and applications of probability and stochastic processes: e.g. central limit theorems, large deviations, stochastic differential equations, models from statistical mechanics, queuing theory.
2
votes
Accepted
How to factorize the joint probability of an arbitrary graph whose nodes are random variables?
As I read it, Bishop is asserting that for each maximal clique $C$ we may define the potential as $\psi_C(x_C) = \prod_S U_S(x_S)$ where $S$ denotes cliques which are subsets of $C$ (and $U$ is the en …
1
vote
Is there a problem with the Wishart distribution?
If you are interested in constructive distributions that you can simulate from (as opposed to something simpler with a known expression for the density) you have a lot of flexibility in constructing p …
0
votes
A test for randomness of direction of vector data
Here is one approach to consider.
Treating the data as points on the surface of the unit sphere, consider the collection of convex subsets on this surface that contain all of your observations. Then, …
2
votes
Accepted
Maximum entropy probability distribution with known quantile
The quantile alone is insufficient to define a maximum entropy density. Intuitively this is because the quantile is a single point and is not enough to prescribe an entire density; you must specify ad …
1
vote
Estimating joint and conditional probabilities with incomplete information
This paper addresses a similar problem I think, although I believe they consider binary outcomes only:
Ramsahai, R.R. (2007). Causal bounds and instruments. In Proceedings of the 23rd Annual Confere …
0
votes
Estimating the mean of a truncated gaussian curve
Others have hit on this, but I thought I'd contribute how I'd write the problem down (briefly):
Let $x_i \sim N(m, 1)$ for $i \in \lbrace 1, \dots, N\rbrace$ and define $y_i \equiv x_i$ if $x_i > 0 …
2
votes
Accepted
Why is Beta the maximum entropy distribution over Bernoulli's parameter?
I think there are two separate things going on here. One is the issue of a maximum entropy distribution. The other is of whether or not distributions are invariant under different parameterizations. …
4
votes
Are all probabilities conditional probabilities?
It is possible to develop probability theory taking conditional probability as one of the basic definitions; see section 3.2 in this book and the references mention there. Renyi was one of the first …
0
votes
An inequality on Difference of Entropies
EDIT: This is wrong -- careless mistake as noted in the comments. I thought I had deleted it, but here it still is.
Working with the RHS of your inequality we have
\begin{eqnarray}\sum_i (P_i - …
0
votes
Marginal density of uniform spherical distribution
I enjoyed thinking about these answers and this is my attempt to put them into (nonrigorous) geometrical terms. Writing the joint density compositionally as
$$p(\mathbf{x}_k \mid |\mathbf{x}| = 1)p(\ …
3
votes
Geometric interpretation of the average of two independent Cauchy distributions
Maybe something like this will work.
Consider $U_1$ and $U_2$ drawn uniformly at random on the unit circle. Because they are uniformly distributed, we may rotate the circle until $U_1$ is at the ``n …
1
vote
Gibbs sampler with linear constraints
I think the difficulty is worse than just finding the right algorithm. The first matter of business is deciding which conditional distribution you want to draw from, because they are non-unique.
I'm …
6
votes
Accepted
Why doesn't Stein effect happen for multinomial distributions?
This is not an answer, but maybe worth thinking about (and I cannot yet leave comments). My intuition about the Stein phenomenon is that while the individual coordinates of the Gaussian random variab …
1
vote
Accepted
Information criteria for ridge regression
The ridge estimator corresponds to the posterior mean under a Normal linear regression model with a conjugate Normal-inverse-gamma prior on the regression coefficients: $\beta \mid \sigma^2, \lambda …
0
votes
Is there a name for "splitting a probability distribution into independent components"?
You can always write down the joint distribution compositionally. In terms of a density function: $$f(\theta_1, \dots, \theta_n) = f_1(\theta_1)f_2(\theta_2 \mid \theta_1)f_3(\theta_3 \mid \theta_1, \ …