Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
4
votes
Accepted
If $X$ is compact, is $[X]^2$ compact, too?
Not necessarily, because in some cases of $X$ Hausdorff, compact, infinite, $[X]^2$ is isomorphic to an open subset of $X\times X$ that is not closed (therefore not compact).
Here's an example. Let $ …
1
vote
Accepted
If $X$ has the "discrete" covering property, how about $X^2$?
This (rather exotic) covering property is often called "Property D". Here you find a nice survey of $D$-spaces.
On p. 11, assuming $\textrm{(CH)}$, a space $Y$ is mentioned that has property $D$, but …
1
vote
1
answer
82
views
Example of a collection of metacompact spaces with non-metacompact box-product
Is there an example of a family $(X_i)_{i\in I}$ of metacompact spaces, such that their box product $\prod_{i\in I}^{\textrm{Box}}X_i$ is not metacompact?
1
vote
Accepted
Compact $R_1$-spaces
The answer is Yes.
Suppose $(X,\tau)$ is $R_1$ and compact. Pick $V$ open and let $x\in V$. For each $y\in X\setminus V$ there are open neighborhoods $U(y)$ of $x$ and $V(y)$ of $y$ such that $U(y)\c …
-2
votes
1
answer
378
views
Bounded metric spaces with non-surjective self-isometry
A metric space $(X,d)$ is said to be bounded if there is $r\in\mathbb{R}$ such that for all $x,y\in X$ we have $d(x,y) \leq r$.
A self-isometry is a map $\iota:X\to X$ such that for all $x,y\in X$ we …
0
votes
1
answer
131
views
"Universal" connected spaces
Let $\kappa$ be an infinite cardinal. Does there exist a topology $\tau_{\kappa+1}$ on $\kappa+1$ such that for any topological space $(X,\tau)$ with $|X|=\kappa$ the following statement is true?
…
0
votes
Corresponding between prime ideals in $C(X)$ and $C^*(X)$
Yes - the correspondence $M^p \mapsto M^{*p}$ (and vice versa) is exactly what you are looking for.
1
vote
0
answers
73
views
Injectively rigid spaces
Given a set $X$, is there a topology $\tau$ such that the identity $\text{id}_X$ on $X$ is the only continuous injective self-map?
(This is Joel David Hamkins's recent question in the category $\math …
1
vote
1
answer
65
views
Hausdorff spaces with asymmetric image relation
For any topological space $(X,\tau)$ we define $$R_{im}(X,\tau) := \{(x,y)\in X^2: (\exists f:X\to X) \text{ continuous and surjective with } f(x) = y\}.$$
Clearly, $R_{im}(X,\tau)$ is reflexive, and …
2
votes
1
answer
154
views
Reconstructing relations with the image relation of a topology
For any topological space $(X,\tau)$ we define $$R_{im}(X,\tau) := \{(x,y)\in X^2: (\exists f:X\to X) \text{ continuous and surjective with } f(x) = y\}.$$
Clearly, $R_{im}(X,\tau)$ is reflexive. This …
1
vote
1
answer
105
views
Open cover not containing a certain subcover
Is there an infinite topological space $(X,\tau)$ with the following property?
There is an open cover ${\cal U}^*$ such that
$X\notin {\cal U}^*$;
every finite subset $F\subseteq X$ is contained in …
1
vote
1
answer
131
views
"Immovable" topological spaces
Let $(X,\tau)$ be a topological space. We define the "moving" relation by setting $$ x \simeq_m y \text{ iff there is a homemomorphism }\varphi: X\to X \text{ such that } \varphi(x) = y.$$
Clearly $\ …
7
votes
2
answers
260
views
Reconstructibility of topological spaces
Let $(X,\tau), (Y,\sigma)$ be topological spaces with $|X|$ infinite and suppose $\varphi:X\to Y$ is a bijection such that for all $x\in X$ we have that $(X\setminus\{x\}) \cong (Y\setminus\{\varphi(x …
4
votes
1
answer
285
views
Stronger form of connectedness than path-connectedness
Given a topological space $C$ and points $c_0, c1\in C$ we say that a topological space $(X,\tau)$ is $(C,c_0,c_1)$-connected if and only if for all $x,y\in X$ there is $f:C\to X$ continuous with $f(c …
1
vote
3
answers
299
views
Topological properties via properties continuous maps [closed]
A topological space $(X,\tau)$ is connected if and only if the only continuous maps $f:X\to\{0,1\}$ (where $\{0,1\}$ carries the discrete topology) are the constant maps.
Are there other examples of …