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This tag is used if a reference is needed in a paper or textbook on a specific result.
2
votes
1
answer
97
views
Concentration of measure on finite powers of $S^\infty$
I am wondering about a natural generalization of theorem 1.4 in the article Dvoretzky's theorem — Thirty years later by Milman. My first thought was to look at Milman's paper that he cites for the res …
7
votes
0
answers
151
views
Is there a complete characterization of hyperimaginaries in $\mathsf{DLO}$?
Recall that in a first-order theory $T$, a hyperimaginary is an equivalence class of some type-definable equivalence relation $E(x,y)$ (with $x$ a possibly infinite tuple of parameters). The $E$-equiv …
0
votes
1
answer
237
views
Covering numbers of uniformly bounded subsets of Gromov-Hausdorff space
For any metric space $X$ and $\varepsilon>0$, let $$\text{cov}(X,\varepsilon)=\min\{n\,|\,X\text{ has a cover by }n\text{ many closed }\varepsilon\text{-balls}\},$$
be the ordinary covering numbers. …
3
votes
1
answer
190
views
Existence of invariant types whose Morley sequences are all indiscernible sets
Fix a complete first order theory $T$ and a set of parameters $A$ in the monster model $\mathcal{U}$. Recall that an $A$-invariant global type is a type $p(x) \in S_x(\mathcal{U})$ which is fixed by a …
3
votes
0
answers
87
views
Proof that superstable theories with no Vaughtian pairs have no imaginary Vaughtian pairs
In 'Elementary pairs of models' by Bouscaren, she mentions with a remark at the end that if $T$ is a superstable theory then $T$ has a Vaughtian pair if and only if $T^\text{eq}$ has a Vaughtian pair, …
4
votes
1
answer
157
views
Preservation theorem for intersection of relations on a fixed set
It is a well known fact that any intersection of equivalence relations on a fix set is itself an equivalence relation. The same holds for a few other common relational theories, such as partial orders …
5
votes
0
answers
122
views
Is there an NSOP theory with FFSOP?
After talking to a couple of people, I have been unable to determine whether this is even known.
Recall that a first-order theory $T$ has the strict order property or SOP if there is a formula $\varph …
3
votes
0
answers
143
views
Does Robinson arithmetic interpret a Kripke model of the double negation translation of $\ma...
It is a well-known fact that while while Robinson arithmetic can interpret surprisingly strong theories, it cannot interpret $\mathsf{I}\Delta_0 + \mathrm{Exp}$, i.e., Peano arithmetic with induction …
4
votes
0
answers
97
views
How hard can it be to extract SOP from an unstable NIP theory?
A very fundamental result of Shelah in neostability theory is the fact that any unstable NIP theory has an instance of the strict order property, a formula $\varphi(x,y)$ (with $x$ and $y$ possibly tu …
2
votes
1
answer
130
views
For which continua $X$ does $X^\mathbb{N}$ have the fixed-point property?
A topological space $X$ has the fixed-point property if any continuous map $f : X \to X$ has a fixed point (i.e., an $x$ such that $f(x) = x$). It's well known that certain topological spaces, such as …
4
votes
0
answers
82
views
When do Borel propositional theories have topologically tame truth assignments?
Let $(P_r)_{r \in \mathbb{R}}$ be an $\mathbb{R}$-indexed family of propositional variables. Let $\mathcal{L}$ be the collection of all propositional sentences formed from the variables $(P_r)_{r \in …
10
votes
2
answers
262
views
Which compact metrizable spaces have continuous choice functions for non-empty closed sets?
Let $X$ be a compact metrizable space and let $\mathcal{K}_{ne}(X)$ be the collection of non-empty closed subsets of $X$ with the Vietoris topology (i.e. the topology induced by the Hausdorff metric f …
7
votes
1
answer
170
views
Can there be a p-point ultrafilter that is 'aggressively non-Ramsey'?
These are fairly standard terms, but for the sake of completeness: An ultrafilter $\mathcal{U}$ on $\omega$ is a p-point if whenever $(A_n)_{n<\omega}$ is a partition of $\omega$ such that $A_n \notin …
2
votes
0
answers
166
views
Which first-order theories have full indiscernible extraction?
Stable theories have the following useful property, which I will state in a sub-optimal way for simplicity's sake:
Fact 1. If $T$ is $\lambda$-stable for some $\lambda \geq |T|^+$, then for any set o …
7
votes
1
answer
366
views
Quantifier elimination in uncountable elementary "Fraïssé classes"
Let $\mathcal{L}$ be an infinite relation language (this question is trivial in a finite relational language). Suppose that $\mathcal{K}$ is the class of finite models of some $\mathcal{L}$-theory (si …