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The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.

5 votes
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Proof of the sum of the reciprocal non trivial zeros cubed

This comes directly from the Hadamard product given in the Wolfram page you refer to by taking logarithmic derivatives and identifying powers of $s$. However, following Harold Stark, the classical for …
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8 votes
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On a certain integral representation for Hurwitz zeta functions

All these are special cases of the Abel--Plana formula: under simple regularity and growth condition which are easily given, for any $a$ with $\Re(a)>-1/2$ we have $$\sum_{n\ge 0}f'(n+a)=-\dfrac{\pi}{ …
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3 votes
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Can this quantity be expressed as $x\cdot \zeta(k)+y, x,y \in \mathbb{Q}$?

Yes, and yes. 1) We have $$|l(a)|_k^k=\sum_{d\mid a}\left(\prod_{p\mid d}\left(1-\dfrac{1}{p^k}\right)\right)\left(\zeta(k)-\sum_{j=1}^{a/d}\dfrac{1}{j^k}\right)\;,$$ which checks with your special …
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6 votes

Derivative of zeta at positive even integers

Partial answer: in my book Springer Graduate Texts in Math 240 page 142 Exercise 92, I give six equivalent formulas for the very similar sum $\sum_{n\ge2}\zeta'(n)$. I suggest first that you prove the …
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9 votes

Malmsten-like integrals for $\zeta(n) $

Three remarks: If you change $x$ into $\exp(-t)$ your integrals are linear combinations of $\int_0^\infty \log(t)\exp(-mt)/(1+\exp(-2t))^n\,dt$. In turn, these integrals are the derivative with respe …
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$\zeta(2n+1)$ - Is this formulation helpful?

This follows directly from the Euler-MacLaurin formula applied to $\sum_{1\le m<N}m^{2k}\log(m)$: the constant term is essentially $\zeta'(-2k)$, itself directly related via the functional equation to …
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5 votes
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Do the roots of this equation involving two Euler products all reside on the critical line?

This problem (and more general ones) was solved completely and unconditionally (i.e., without any RH) by P.R. Taylor before the second world war, but I don't remember the reference, it should be easy …
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13 votes
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A conjectured series expression for the Riemann $\xi$-function and/or Completed L-series. Co...

Your conjecture is true, and follows trivially from the Poisson summation formula. For instance, use Theorem 9.4.2 in my book joint with K. Belabas "Numerical Algorithms for number theory", GSM 254, A …
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Is there a Riemann Hypothesis criterion utilizing sum of squares of divisors?

I would expect no: the big difference between $\sigma_1$ and $\sigma_k$ for $k\ge2$ is that in the latter case $\sigma_k(n)/n^k$ is trivially bounded by $\zeta(k)$, which doesn't leave much room for a …
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4 votes

Has Apéry's proof of the irrationality of $\zeta(3)$ ever been used to prove the irrationali...

I also want to mention the formula (origin unknown) $$\dfrac{56\zeta(3)}{3}=\sum_{n\ge1}\dfrac{64^n}{n^3D_nD_{n-1}}\;,$$ where $D_n=W_4(2n)$ is the $n$th Domb number, equivalent to the continued fract …
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1 vote

Asymptotic behavior of weighted sums involving the fractional part function

Not an answer but a conjectural answer for the value of $C(m)$ supported by extensive numerical evidence: $$C(m)=\dfrac{1}{m-1}\sum_{2\le k\le m-1}\binom{m-1}{k}\zeta(k)+\sum_{2\le k\le m-2}\dfrac{1}{ …
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