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Questions about the branch of algebra that deals with groups.
17
votes
2
answers
590
views
Infinite groups with oligomorphic conjugation action
The action of a group $G$ on a set $X$ is called oligomorphic if the diagonal action on $X^n$ has finitely many orbits for each $n$.
Question: Is there an infinite (maybe even finitely generated) …
4
votes
Commutator Subgroup - Group Theory
The commutator subgroup of the free group $\langle a,b \rangle$ is freely generated by the set
$$\lbrace [a^n,b^m] \mid n,m \in \mathbb Z, nm \neq 0 \rbrace.$$
2
votes
How similar/different are dense subgroups of a compact group.
Since you are interested in positive results (rather than counterexamples) in the case when the pro-finite completions of two groups agree, let me mention the following result from
Martin R. Bridson …
14
votes
Accepted
Centraliser of the complex conjugation in the absolute Galois group
If some element centralizes the complex conjugation, then it must preserve the real numbers as a set. Now, since any automorphism of the real numbers preserves the set of squares, it must preserve the …
12
votes
Accepted
Is every finitely generated group colimit of residually finite groups
The answer is: This does not hold in general.
If the group in question is finitely generated, then the maps into the colimit will eventually be surjective. If the group in question is also finitely p …
6
votes
Accepted
Sofic/hyperlinear groups
I think that this is known in the operator algebra commmunity, but it is also a consequence of the proof in the sofic case, which was obtained in
Elek, Gábor, Szabó, Endre, On sofic groups. J. Group …
2
votes
Linear irreducible representations of residually finite groups
As Mark Sapir pointed out, this is of course false. There are tons of infinite dimensional irreducible representations of residually finite groups. In fact, I think that any finitely generated group f …
1
vote
Groups with triple system of self-normalizing subgroups
This is just an idea, not a solution. In
Marc Burger, Shahar Mozes, Lattices in product of trees, Inst. Hautes Etudes Sci. Publ. Math. 2000 (92) pp. 151-194
the authors study a class of groups G whi …
13
votes
A non-trivial property of all groups
This concerns the updated question. The answer is yes.
If $G$ is represented as the union of a finite number of subsets $A_1, \dots,A_n$, then one of the subsets generates a finite index subgroup of …
7
votes
A (nameless?) product in the category of groups, and its properties
I do not know whether this answers you question, but such a group is an extension of $K/K \cap L \times K / K \cap L$ by $K \cap L$, i.e.
$$1 \to K \cap L \to KL \to K/K \cap L \times L/K \cap L \to …
17
votes
(Non)free differential calculus
There are always derivations of the form $\delta_b(a) = ab - b\varepsilon(a)$ for $b \in R[G]$, which are called inner derivations. Derivations modulo inner derivations are classified by the first gro …
22
votes
1
answer
1k
views
Generation of finite index subgroups
Related to a question by Mark Sapir (see here) and a question by Kate Juschenko (see here), let me ask the following:
Question: Let $G$ be a finitely generated group and let $\varepsilon>0$. Is th …
54
votes
2
answers
2k
views
How many relations of length $n$ can exists in a group without enforcing shorter relations?
Let $G$ be a group with two generators. Suppose that all non-trivial words of length less or equal $n$ in the generators and their inverses define non-trivial elements in $G$.
Question: How many o …
18
votes
0
answers
821
views
Quotients of residually finite groups by amenable normal subgroups
My questions are:
Is there any group, which cannot be written as the quotient of a residually finite group by an amenable normal subgroup? Is it possible for large classes of groups?
and
Is …
17
votes
No injective groups with more than one element?
Let $G$ be a non-trivial injective group and $g \in G$ non-trivial. From category theory, $G \times G$ is injective as well. But, now $G \times G$ embeds into a group $H$, where $(g,e)$ and $(e,g)$ ar …