Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
3
votes
Size of sets with complete double
Note that any solution will be of the form $S=\{0,1,s_2,\cdots,s_j,n-1,n\}$ and then $S'=\{0,1,n-s_j,\cdots,n-s_2,n-s_1,n-1,n\}$ is also a solution. If $S=S'$ one might call it a symmetric solution. …
2
votes
Accepted
Recovering Sidon sets from difference sets, part 2.
N0. It is NOT the case that it is true in general. It is true for all cases with both $m \le 5$ and prime $n \lt 100$. It is also true for $m=6$ and $n = 31$. But actually it is false ( for $m=6$) o …
3
votes
Accepted
Recovering Sidon sets from difference sets
If $A$ is a Sidon set in $\mathbb{Z}/n\mathbb{Z}$ and $|A|=m$ then $A-A$ has $m^2+m+1$ members including $0.$ For $\lambda$ co-prime to $n$, $B=\lambda A$ is also a Sidon set and $B-B=\lambda(A-A).$ …