Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 7732

Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.

13 votes
Accepted

A riddle about zeros, ones and minus-ones

Another answer (I guess they must be equivalent): Write each original line as a difference of two 0/1 vectors. Adapt this representation to the modified lines by changing only the subtrahends. You n …
Yuval Filmus's user avatar
  • 1,906
11 votes

A rather curious identity on sums over triple binomial terms

The combinatorial identity $$ \sum_{k=0}^{n-1} \binom{n+1}{k} \binom{n+1}{k+1} \binom{n+1}{k+2} = 2 \sum_{k=0}^{n-1} \binom{n+1}{k} \binom{n}{k} \binom{n+1}{k+2} $$ has a simple combinatorial proof. T …
Yuval Filmus's user avatar
  • 1,906
8 votes

What is the best algorithm for even rank magic square?

There is an extremely simple method attributed to Conway by Eric Weisstein, who describes it in a MathWorld article. All formulas below assume that row and column indices are 1-based. We have to dist …
Yuval Filmus's user avatar
  • 1,906
6 votes

Beyond Hilton-Milner Theorem for an Intersecting Family?

There are at least three types of results that spring to mind. One is the Ahlswede-Khachatrian theorem ("the complete intersection theorem"), which for each $n$ and $k < n/2$ will give you tight upper …
Yuval Filmus's user avatar
  • 1,906
5 votes
1 answer
445 views

Orthogonal basis for the multilinear polynomials with zero "trace"

We say that a multilinear polynomial $P(x_1,\ldots,x_n)$ in $n$ commuting variables over $\mathbb{R}$ has zero trace if $$ \frac{d}{dt} P(t,\ldots,t) = 0. $$ Equivalently, $$ \left(\sum_{i=1}^n \frac{ …
Yuval Filmus's user avatar
  • 1,906
4 votes

3_partite graphs

There is (probably) no nice condition for a graph to be 3-colorable, since deciding whether a graph is 3-colorable is NP-complete. Moreover, assuming the Exponential Time Hypothesis, deciding whether …
Yuval Filmus's user avatar
  • 1,906
3 votes

Connective constant for self-avoiding walks on a skip-chain

A step is a movement of magnitude 1, a hop of magnitude 2. Denote by $X$ a visited place, by $O$ a place not visited, and by $Y$ the current position. A self-avoiding walk hovers around the states $E …
Yuval Filmus's user avatar
  • 1,906
3 votes

Asymptotics for forbidden subwords

If you fix $B$ then the situation is described by a DFA (deterministic finite automaton), i.e. the set of permissible words is a regular language, and so has a rational generating function; therefore, …
Yuval Filmus's user avatar
  • 1,906
3 votes

Generalizations of the Birkhoff-von Neumann Theorem

The theorem still holds if we ask each row and column to sum to some integer $m$; permutation matrices are replaced with zero-one matrices having the same constraints. See Watkins and Merris, Convex S …
Yuval Filmus's user avatar
  • 1,906
3 votes
Accepted

Orthogonal basis for the multilinear polynomials with zero "trace"

The basis appears in Murali K. Srinivasan's paper Symmetric chains, Gelfand-Tsetlin chains, and the Terwilliger algebra of the binary Hamming scheme, though perhaps not as explicitly. The author shows …
Yuval Filmus's user avatar
  • 1,906
2 votes

actions of the hyperoctahedral group

Given $w \leq n$, consider the graph $G$ whose vertex set is $F_2^n \times \binom{[n]}{w}$, and two vertices $(v,S),(v',S')$ are connected if $v|_S = v'|_S$ or $v|_{S'} = v'|_{S'}$, where $v_S \in F_2 …
Yuval Filmus's user avatar
  • 1,906
2 votes

enumerative combinatorics with fixed number repeats

Suppose we have n elements, we want to generate r elements (without order), and want exactly k elements to be repeated. We can separate the result into a part containing all the repeated elements (th …
Yuval Filmus's user avatar
  • 1,906