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Enumerative combinatorics, graph theory, order theory, posets, matroids, designs and other discrete structures. It also includes algebraic, analytic and probabilistic combinatorics.
4
votes
3_partite graphs
There is (probably) no nice condition for a graph to be 3-colorable, since deciding whether a graph is 3-colorable is NP-complete. Moreover, assuming the Exponential Time Hypothesis, deciding whether …
2
votes
enumerative combinatorics with fixed number repeats
Suppose we have n elements, we want to generate r elements (without order), and want exactly k elements to be repeated.
We can separate the result into a part containing all the repeated elements (th …
6
votes
Beyond Hilton-Milner Theorem for an Intersecting Family?
There are at least three types of results that spring to mind. One is the Ahlswede-Khachatrian theorem ("the complete intersection theorem"), which for each $n$ and $k < n/2$ will give you tight upper …
3
votes
Connective constant for self-avoiding walks on a skip-chain
A step is a movement of magnitude 1, a hop of magnitude 2.
Denote by $X$ a visited place, by $O$ a place not visited, and by $Y$ the current position. A self-avoiding walk hovers around the states $E …
3
votes
Asymptotics for forbidden subwords
If you fix $B$ then the situation is described by a DFA (deterministic finite automaton), i.e. the set of permissible words is a regular language, and so has a rational generating function; therefore, …
8
votes
What is the best algorithm for even rank magic square?
There is an extremely simple method attributed to Conway by Eric Weisstein, who describes it in a MathWorld article.
All formulas below assume that row and column indices are 1-based.
We have to dist …
13
votes
Accepted
A riddle about zeros, ones and minus-ones
Another answer (I guess they must be equivalent):
Write each original line as a difference of two 0/1 vectors.
Adapt this representation to the modified lines by changing only the subtrahends.
You n …
3
votes
Generalizations of the Birkhoff-von Neumann Theorem
The theorem still holds if we ask each row and column to sum to some integer $m$; permutation matrices are replaced with zero-one matrices having the same constraints. See Watkins and Merris, Convex S …
11
votes
A rather curious identity on sums over triple binomial terms
The combinatorial identity
$$
\sum_{k=0}^{n-1} \binom{n+1}{k} \binom{n+1}{k+1} \binom{n+1}{k+2} =
2 \sum_{k=0}^{n-1} \binom{n+1}{k} \binom{n}{k} \binom{n+1}{k+2}
$$
has a simple combinatorial proof.
T …
5
votes
1
answer
445
views
Orthogonal basis for the multilinear polynomials with zero "trace"
We say that a multilinear polynomial $P(x_1,\ldots,x_n)$ in $n$ commuting variables over $\mathbb{R}$ has zero trace if
$$ \frac{d}{dt} P(t,\ldots,t) = 0. $$
Equivalently,
$$ \left(\sum_{i=1}^n \frac{ …
3
votes
Accepted
Orthogonal basis for the multilinear polynomials with zero "trace"
The basis appears in Murali K. Srinivasan's paper Symmetric chains, Gelfand-Tsetlin chains, and the Terwilliger algebra of the binary Hamming scheme, though perhaps not as explicitly. The author shows …
2
votes
actions of the hyperoctahedral group
Given $w \leq n$, consider the graph $G$ whose vertex set is $F_2^n \times \binom{[n]}{w}$, and two vertices $(v,S),(v',S')$ are connected if $v|_S = v'|_S$ or $v|_{S'} = v'|_{S'}$, where $v_S \in F_2 …