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A C*-algebra is a complex Banach algebra together with an isometric antilinear involution satisfying (a b)* = b* a* and the C*-identity ‖a* a‖ = ‖a‖². Related tags: [banach-algebras], [von-neumann-algebras], [operator-algebras], [spectral-theory].

24 votes
2 answers
1k views

Does left-invertible imply invertible in full group C*-algebras (discrete case)?

The following question/problem has been bugging me on and off for some time now: so I thought it might be worth broaching here on MO, as a case of "ask the experts". Let $G$ be a discrete group. Kapl …
Yemon Choi's user avatar
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20 votes
Accepted

Are algebraically isomorphic $C^*$-algebras $*$-isomorphic?

Answering the question in the body of the original post, which seems to be more restricted than the implicit question in the title of the post.... The answer is YES. See L. Terrell Gardner, On is …
Yemon Choi's user avatar
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20 votes
Accepted

Do torsion-free groups give projectionless group ($C^\ast$) algebras?

Heh, you've picked an open problem: this is the Kadison-Kaplansky conjecture... I would answer it, but first I have to find a sufficiently big margin in which to write the proof. To be less flippant, …
Yemon Choi's user avatar
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16 votes
0 answers
538 views

$C^*$-algebra generated by those operators that are bounded on every $\ell_p$

Suppose $T: c_{00} \to c_{00}$ is a linear map such that, when regarded as an infinite matrix, there is a uniform bound on the $\ell_1$-norms of its columns, and a uniform bound on the $\ell_1$-norms …
Yemon Choi's user avatar
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13 votes
1 answer
298 views

What does it tell us, if we know a unital C*-algebra has approximately inner (half-)flip?

This is a somewhat vague question, but I think it is not too open-ended and should admit well-circumscribed answers by specialists in operator algebras.$\newcommand{\Cst}{{\rm C}^*}$ It arises from so …
Yemon Choi's user avatar
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11 votes
2 answers
630 views

Quasinilpotent elements of group C-star algebras

If $G$ is a discrete torsion-free group, can its (reduced or full) group C-star algebra contain non-zero quasinilpotent elements? I've seen various examples in the group von Neumann algebra setting (u …
Yemon Choi's user avatar
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11 votes
Accepted

Is a C*-algebra with an isomorphic predual a von Neumann algebra?

Via my colleague Garth Dales, some observations which answer your question in the negative, even in the abelian case:$\newcommand{\N}{{\mathbb N}}$ We know that $K$ is hyper-Stonean iff $C(K)$ is …
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10 votes
Accepted

Is this a functor on the category of $C^{*}$ algebras?

Here is another attempt at proving no such functor exists — I apologize to Chris and to Manny if something like this is already in the papers which they cite.$\newcommand{\Mat}{{\bf M}}\newcommand{\Cp …
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10 votes

Quasinilpotent elements of group C-star algebras

Prompted by Douglas Somerset's answer to look harder, I've found a paper of Behncke that also gives what I need, according to MathSciNet, by proving a stronger result: MR0283582 (44 #813) Behncke, H. …
10 votes
Accepted

$K$-theory and surjective norm-decreasing $*$-homomorphisms between $C^*$-algebras

Yes to both.$\newcommand{\Cst}{{\rm C}^*}$ The standard example for the first is: take a discrete group $G$ and let $A$ be its full $\Cst$-algebra, $B$ its reduced $\Cst$-algebra. There is a canonica …
Yemon Choi's user avatar
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10 votes
1 answer
1k views

When are certain group C*-algebras exact?

This is somewhere between a "reference request" and "ask an expert", but I hope it is not too trivial or off-topic. Anyway. There has been a lot of attention given to showing that for certain discret …
Yemon Choi's user avatar
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9 votes

Is the algebra of compact operators flat?

Assuming that your $\otimes$ denotes min-tensor product of ${\rm C}^\ast$-algebras, then the answer to the question in the body of your post -- which is NOT the same as the question in the title of yo …
Yemon Choi's user avatar
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9 votes

Real rank zero of group $C^*$-algebras

Here is a partial answer, and a pointer towards some literature that should be relevant.$\newcommand{\Cst}{{\rm C}^*}$ Doing some searching online brings up an old result of Kaniuth (Proc. AMS, 1993) …
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8 votes

The difference between $l^1(G)$ and the reduced group $C^*$ algebra $C_r^*(G)$

A couple of quick comments. Firstly, I'd advise you to think about what you know about Q1 in the case $G= {\mathbb Z}^d$ (or even just the case $G={\mathbb Z}$) -- because in such settings you can th …
Yemon Choi's user avatar
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8 votes
Accepted

A precise definition of contractible Banach algebras

$A$ is contractible if $H^1(A,X)=0$ for all Banach $A$-bimodules $X$ (here $H^1$ denotes continuous Hochschild cohomology for Banach algebras, as defined in the works of Johnson or Helemskii). It is a …
Yemon Choi's user avatar
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