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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.

15 votes
2 answers
1k views

Approximating operators on Banach spaces by bounded operators on a proper dense subspace

While digging through old piles of notes and jottings, I came across a question I'd looked at several years ago. While I was able to get partial answers, it seemed even then that the answer should be …
Yemon Choi's user avatar
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6 votes
Accepted

Is $H^\infty$ a second dual space?

If you only require isomorphism in the sense of an invertible, continuous linear bijection, then the answer is yes. If you require isometric linear isomorphism, the answer is no (because the unique is …
Yemon Choi's user avatar
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5 votes
Accepted

Is $L(\ell_2,\ell_2)$ dense in $L(\ell_2,c_0)$?

Choose finite sets $A_n\subset{\bf N}$ with $\max(A_n)<\min(A_{n+1})$, and then define $T:c_{00}\to c_0$ by $T(e_n)=\chi_{A_n}$. It is easy to check that $T$ extends to a norm 1 linear map $\ell^2\to …
Yemon Choi's user avatar
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1 vote

A proof about an unconditional basis theorem

I'm not a Banach-space specialist, and don't have a copy of Lindenstrauss-Tzafriri to hand (though maybe the Albiac-Kalton book would be a friendlier read, if your library has a copy?) but it seems to …
Yemon Choi's user avatar
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3 votes
Accepted

Convergence of operators to the identity on Banach spaces

Contrary to my original muddled guess, the answer is no: the problem is that your `extension operators' don't give enough control over what happens in the gap between $U_\infty$ and $U_r$. For a conc …
Yemon Choi's user avatar
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9 votes
Accepted

opposite Banach space

Does this paper of Kalton do the trick? (disclaimer: I haven't read through the details)
Yemon Choi's user avatar
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6 votes
Accepted

Question about a characterization of Grothendieck spaces

(Posting this comment as an answer, just so the question doesn't still show up as "unanswered".) Your first claim is not justified (as you yourself suspected). If $T:X\to Y$ has separable range, th …
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2 votes
Accepted

Complemented subspace constructed from finite pieces

No. Take $X=\ell_\infty({\bf N})$ and take $E_n = \operatorname{span}(e_1,\dots, e_n)$. Then $Y=c_0({\bf N})$ which is well-known – by a non-trivial argument – to be uncomplemented in $X$ (in the sens …
Yemon Choi's user avatar
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3 votes

Preannihilators of subspaces of separable duals

The answer to Q2 is negative. One way to see this (which might not be the first, and might not be the easiest) is to combine the following results. A separable dual (Banach) space has the Radon-Niko …
Yemon Choi's user avatar
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17 votes
Accepted

Banach spaces with few linear operators ?

Examples were constructed (about two years ago?) by Argyros and Haydon. See this blog post for some non-technical discussion. It seems worth noting, as one is almost obliged to, that the space origina …
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6 votes
2 answers
1k views

Closed, complemented subspaces of $l^1(X)$ when $X$ is uncountable

... are all isomorphic to $l^1$ on some other index set. At least, that much I "know" from 2nd-hand sources, since the original proof is apparently in a paper of Köthe from the 1930s 1960s (in German) …
Yemon Choi's user avatar
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11 votes
Accepted

Are proper subspaces of Banach spaces which are isomorphic to the ambient Banach space neces...

The first counterexample that comes to my mind, which is probably overkill (memory is easier than thought!) is J. Bourgain, A counterexample to a complementation problem. Compositio Mathematica, Volu …
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7 votes
0 answers
177 views

Does this ideal in $B(L_1)$ have a (bounded) right approximate identity?

I will take a roundabout way to defining this ideal, because (a) this route is how my collaborators and I came to it (b) this alternative definition, rather than the standard one, may suggest a direc …
Yemon Choi's user avatar
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1 vote
1 answer
117 views

Does taking the modulus preserve weak $p$-summability of sequences in $L_q$?

For this question, all Banach spaces are over the reals. Let $1\leq p<\infty$. Recall that a sequence $(x_n)$ in a Banach space $E$ is weakly $p$-summable if $$ \Vert (x_n) \Vert_{p,w} := \sup_{\gamm …
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8 votes
0 answers
194 views

History of the Lewis-Stegall theorem on factorization of representable operators

The following questions are about the history of a particular result in functional analysis, hence not "mathematical questions" per se; but I think they are relevant to the business of writing researc …
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