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3
votes
Accepted
Are Hausdorff compactifications of a Tychonoff space $X$ in one-to-one correspondence with c...
Here's a counterexample if you don't assume your algebra is self-adjoint. Let $X$ be the unit disk in $\mathbb{C}$ endowed with the discrete topology. Let $B$ be the algebra of complex-valued functi …
8
votes
Accepted
Compactly supported cohomology of homotopy equivalent manifolds
Then $M$ and $N$ are homotopy equivalent, but their one-point compactifications are not (the first being a torus and the second having the homotopy type of $S^2\vee S^1\vee S^1$). …