Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
2
votes
When is a pair of space curves that intersect (plenty) a complete intersection?
Edit. This is an answer to the original question (in which $c=1$.)
I think these examples do not exist. In fact, there is the following result, that can be found in
S. Diaz: Space curves that intersec …
5
votes
Accepted
Looking for an inequality between Chern and Todd classes (something in style of Bogomolov-Mi...
By the formulae in [Barth-Peters-Van de Ven, Chapter V] one has, for a surface which is complete intersection of type $(d_1, \ldots, d_{n-2})$ in $\mathbb{P}^n$:
$$c_1^2(X)= \big(\sum d_i-(n+1)\big)^2 …
5
votes
Surface of type $(2,2)$ on the Segre cubic scroll $\mathbb{P}^1 \times \mathbb{P}^2 \subset ...
This surface $X$ satisfies $p_g(X)=q(X)=0$. Moreover, if $H_X$ is the hyperplane section, by adjunction we find $$K_X^2=2, \quad K_X H_X=-4.$$
Therefore no multiple of the canonical divisor can be eff …