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The Riemann zeta function is the function of one complex variable $s$ defined by the series $\zeta(s) = \sum_{n \geq 1} \frac{1}{n^s}$ when $\operatorname{Re}(s)>1$. It admits a meromorphic continuation to $\mathbb{C}$ with only a simple pole at $1$. This function satisfies a functional equation relating the values at $s$ and $1-s$. This is the most simple example of an $L$-function and a central object of number theory.

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Is this differential equation for zeta on the critical line? One can compute it from its der...

The zeta function can be written $\zeta(1/2+it)=Z(t)e^{-i\vartheta(t)}$ where $Z(t)$ are real analytic and $\vartheta(t)$ is a simple function related to $\Gamma(s)$. The relation between $\zeta(1/2 …
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2 votes

Bounds on horizontal minima of the Riemann zeta function

This is not exactly an answer, but too long for a comment. Perhaps I have not been sufficiently clear in the comments. In the paper: T. Kotnik, Computational estimation of the order of $\zeta(1/2+i t …
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2 votes

Do the complex zeros of $\big(\zeta(s-1) -\zeta(s)\big) \pm \big(\zeta(1-s) - \zeta(2-s)\big...

I do not think this is so difficult as the Riemann hypothesis, I will only explain why this is so without giving complete proof. First on the line $s=1+it$ the functions are $$(\zeta(it)-\zeta(1+it)) …
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1 vote

$\sum_{d\leq x} (\mu(d)/d) \log x/d$: elementary estimates?

In chapter 4, p. 15-18 of the book H. Iwaniec, Lectures on the Riemann Zeta Function, American Mathematical Society, University Lecture Series nº 62, 2014 there is an elementary proof of the prime …
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Do we know an upper bound for the multiplicity of the non-trivial zeros of Zeta?

It is known that the number of zeros with $T-1 < Im(\rho)<T+1$ is $O(\log(T))$. Therefore the multiplicity of a zero $\beta+\gamma i$ will be less than $C \log|\gamma|$ for some absolute constant $C …
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A recurrence relation for $\zeta(2n)$ - reference request

I have this recurrence in my collection of problems for my lessons in Analytic Number Theory. I have there the reference: P. Ribenboim, Classical Theory of Algebraic Numbers, Springer, New York, 200 …
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1 vote

Integrals involving $1/|\zeta(1+i t)|^2$: closed expressions?

This is not properly an answer, after the comments of Tao it is difficult to give an answer. Only an explanation of my comment above. I still think that my series and the integral are equal. We can w …
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Zeroes of real and imaginary parts of $\zeta(1+it)$ separately (if any for $t>1$ say)

The solutions of $\Re\zeta(1+it)=0$ are scarce. They limit small intervals where $\Re\zeta(1+it)<0$. The probability in the sense of the limit of the quotient of the measure of the set $\{0<t<T: \Re\ …
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3 votes

Odlyzko's reformulation of Montgomery's pair correlation conjecture

I will say that the natural normalisation of the zeros of zeta is $$\tilde\gamma=\frac{1}{\pi}\vartheta(\gamma)$$ where $$\vartheta(t)=\Im(\log\Gamma(\frac14+\frac{it}{2}))-\frac{t}{2}\log\pi=\frac{t} …
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zeta(3) in terms of derivatives of zeta at 1/2 and pi

In fact for odd $n\ge3$ we have $$\Bigl.\frac{d^{n}}{ds^n}\log\zeta(s)\Bigr|_{s=\frac12}= \frac{(n-1)!}{2}\Bigl(2^n L(n,\chi)+(2^n-1)\zeta(n)\Bigr)$$ The proof (due to Voros) is the following: It …
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A expression for the tangent function involving $\zeta(n),n=2,3,\ldots$

When I was writing my answer, Dan Romik answer appeared. Mine is the same but with more detail. We have $$\log\Gamma(1-x)=\gamma x+\sum_{n=2}^\infty\zeta(n)\frac{x^n}{n}$$ (this is known and is also a …
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How good can we approximate with algebraic curve the egg shaped vanishing of $\Re \zeta(s)$ ...

The figure of egg is not an elliptic curve. Since the curve pass through the point $(-2,0)$ and $(1,0)$ the equation will be of type $$y^2=(ax+b)(x+2)(x-1)$$ We find the numbers $y_0$ and $y_1$ wh …
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What happens to $\zeta(s)$ when all its $\Im(\rho_n)$ are "scaled" linearly?

I assume Riemann hypothesis on all this answer. I want a closed form for $$f(s,x):= \prod_{n=1}^\infty\Bigl(1-\frac{s}{\frac12+i x\gamma_n}\Bigr) \Bigl(1-\frac{s}{\frac12-i x\gamma_n}\Bigr).$$ Of co …
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5 votes

What happens to $\zeta(s)$ when all its $\Im(\rho_n)$ are "scaled" linearly?

... continue the above answer Therefore $$\prod_\gamma\Bigl(1-\frac{s}{\rho}\Bigr)\Bigl(1-\frac{s}{1-\rho}\Bigr)= \frac{\frac14+\frac{t^2}{x^2}}{\frac14-\frac{1}{4x^2}}\frac{\pi^{-\frac{it}{2x}}} {\ …
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6 votes
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A closed form of infinite products of complex zeros involving $\Im(\rho_n)$. Does a proof of...

The proposed formula is not true if RH is not true. Let $\Theta$ be the upper bound of the real parts of the zeros of $\zeta(s)$. Your product has zeros at $\mu$, $1-\mu$, $\overline{\mu}$ and $\ov …
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