Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with lie-groups
Search options not deleted
user 7311
Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.
8
votes
Accepted
Lie group action with no slice
Recall that if a free action of G on M has a slice S at a point x then the natural map of G x S into M given by (g,s) maps to gs would be a diffeomorphism onto a tubular neighborhood of the orbit Gx. …
- 15.3k
6
votes
Action of the group of isometries on a manifold
It is easy to see that any metrically homogeneous, locally compact, metric space, $X$, is complete. If $p$ is some point of $X$ then, by local compactness, for some $\epsilon > 0$, the closed $\epsilo …
- 15.3k
3
votes
Accepted
3
votes
What are the invariant Pseudo-differential operators on a Lie group?
It seems to me that an interesting "first step" or sub-problem---and one that should be fairly straightforward, is to characterize the space of invariant symbols of pseudo differential operators on a …
- 15.3k
23
votes
Accepted
Monotone functions are differentiable a.e. and Hilbert's Fifth Problem: what's the connection?
Well, I cannot say for certain, but I did know Gleason well (he was my thesis advisor, and we wrote a paper together after that) and I have written an essay about Gleason's work on the Fifth Problem ( …
- 15.3k
56
votes
What is the situation with Hilbert's Fifth Problem?
The OP says:
" ...Recently, Palais wrote about it in the Notices but he only treats the old story from the 1950s and seems not to be aware of Olver’s facts."
Actually, I am aware of Olver's work and …
- 15.3k
4
votes
Does a finite-dimensional Lie algebra always exponentiate into a universal covering group
The short answer to 3. is "no". The simplest example is the circle group, $e^{it}$ of complex numbers of absolute value 1, (thought of as a $1 \times 1$ matrices), its Lie algebra $A$ consists of the …
- 15.3k
17
votes
1
answer
500
views
Is a smooth action of a semi-simple Lie group linearizable near a stationary point?
Suppose that $G$ is a semi-simple Lie group that acts smoothly (i.e., $C^\infty$) on a smooth, finite dimensional manifold $M$. Does it follow that the action of $G$ is linearizable near any stationar …
- 15.3k