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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

0 votes

Components of a Fiber Product

Edit: I gave a proof of a false statement earlier. It can be salvaged to the folowing much weaker statement: the point $(x,y)$ is in the dominant irreducible component if we have $df|_x(T_x)+dg|_y(T_y …
Dmitry Vaintrob's user avatar
8 votes

Number of points of algebraic curve

Edit The original diagonalization argument function I gave didn't satisfy the inequality. The following answer works. A diagonalization argument works here to show there aren't! Take an enumeration $X …
Dmitry Vaintrob's user avatar
3 votes

Cotangent complex of certain dg-scheme

Well, unless I am mistaken, whenever you have a cdg ring given by dg generators and relations, then the cotangent space at zero is simply the cone of the differential $T^*\text{Spec}(S^*{\text{generat …
Dmitry Vaintrob's user avatar
2 votes

Topological version of K-theory of coherent sheaves

I don't think K-homology will satisfy your requirements. The reason people think of G-theory as dual to K-theory is because for proper $X$, the graded space $Ext^*(F,Q)$ is finite-dimensional for $F$ …
Dmitry Vaintrob's user avatar
5 votes

Galois twist of a variety

Just follow your nose. Functoriality of cohomology gives a map $\operatorname{Aut}(X_\bar{\mathbb{Q}})\to \operatorname{Aut}\big(H^q_{\text{ét}}(X_{\bar{\mathbb{Q}}}, \mathbb{Q}_\ell)\big)$ (actually, …
Dmitry Vaintrob's user avatar
4 votes
Accepted

Formal completion of an elliptic curve along the $0$ sectioin and the formal expansion of fu...

Yes, what you are saying is true, at least over an algebraically closed base $k$ of characteristic $0$. In fact, all you need is that $S$ is affine and that the normal bundle $I/I^2$ is trivial (as a …
Dmitry Vaintrob's user avatar
2 votes
0 answers
73 views

What should I call a log scheme with free reduced monoids?

This is a terminology question about a class of log varieties. Given an fs (fine and saturated) log variety $(X, M)$ (for $M$ the defining sheaf of monoids), any geometric point $x\in X$ has a finitel …
Dmitry Vaintrob's user avatar
7 votes
1 answer
748 views

What's a (infinity-) semi-stack?

A stack is an object that mixes the notions of (algebraic) space and group. The key insight of stack theory is that most things you would want to do with spaces you can do with stacks: namely, you hav …
Dmitry Vaintrob's user avatar
4 votes
1 answer
283 views

Weak homotopy equivalence of sites

There are several notions of weak homotopy equivalence for topological spaces. The standard one can be formulated as follows: a map of spaces $X\to Y$ is a homotopy equivalence if the map of simplicia …
Dmitry Vaintrob's user avatar
2 votes
1 answer
247 views

Is the property of being a dg generator open?

Suppose $\mathcal{C}$ is a dg category (over some base) with all colimits. We say that $X\in \mathcal{C}$ is a generator if $\mathcal{C}$ is equivalent to $\operatorname{End}_\mathcal{C}X$-modules (vi …
Dmitry Vaintrob's user avatar
2 votes

How much of a variety can be reconstructed from codimension-zero data?

I realized the answer is almost certainly "no", so I asked a better version of this question at How much of a variety can be reconstructed from codimension-zero data?. I think that if you take two hy …
Dmitry Vaintrob's user avatar
2 votes
0 answers
290 views

Local weak factorization

This is a follow-up to question Locally toric resolutions of compactifications, answered by Jason Starr. In a series of papers (see https://arxiv.org/abs/math/9904076), Jaroslaw Wlodarczyk proves th …
Dmitry Vaintrob's user avatar
1 vote

Separable extensions & topology vs inseparable extensions and algebra

I would guess that the intuition is that separable extensions extend uniquely over "infinitesimal thickenings", i.e. deformations over a nilpotent base. This makes their classification problem "rigid" …
Dmitry Vaintrob's user avatar
12 votes

Is forming the Albanese variety a monad?

I'll go ahead and turn my comment into an answer. It does form a monad, but (probably) not a very interesting one. Namely, first note that any pair of adjoint functors $L:\mathcal{C}\leftrightarrows \ …
Dmitry Vaintrob's user avatar
20 votes

Algebraic machinery for algebraic geometry

I want to offer a possibly heretical opinion based on conversations I've had with people who do algebraic geometry, especially Joe Harris. I think that it is not necessary to know very much commutativ …

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