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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
40
votes
5
answers
3k
views
The sequence $a_{n+1}=\left\lceil \frac{-1+\sqrt{5}}{2}a_{n}-a_{n-1} \right\rceil$ is periodic
Let $(a_{n})_{n \ge 1}$ be a sequence of integers such that for all $n \ge 2$:
$0\le a_{n-1}+\frac{1-\sqrt{5}}{2}a_{n}+a_{n+1} <1$.
Prove that the sequence $(a_{n})$ is periodic.
This …
29
votes
6
answers
2k
views
$m$-fold composite $p^{(m)}(x) \in \mathbb{Z}[x]$ implies $p(x) \in \mathbb{Z}[x]$
Let $p(x)$ be a polynomial, $p(x) \in \mathbb{Q}[x]$, and $p^{(m+1)}(x)=p(p^{(m)}(x))$ for any positive integer $m$.
If $p^{(2)}(x) \in \mathbb{Z}[x]$ it's not possible to say that $p(x) \in \mathbb{Z …
24
votes
2
answers
1k
views
If $x_{n+1}= \frac{nx_{n}^2+1}{n+1}$ then $x_{n}=1$
I asked this question at MSE, but I think it's more appropriated to MO.
Let $x_{n}$ be a sequence, such that $x_{n+1}= \dfrac{nx_{n}^2+1}{n+1}$ and $x_n>0$ for all $n$.
There is a positive inte …
10
votes
1
answer
343
views
Finding $q(x)$ such that $p(q(x))$ is reducible over $\mathbb{Q}[x]$
Let $p(x) \in \mathbb{Z}[x]$, such that $\deg (p) \ge 3$.
Can we always find $q(x) \in \mathbb{Z}[x]$, such that $\deg (q) < \deg(p)$ and $p(q(x))$ is reducible over $\mathbb{Q}[x]$?
Is there a …
10
votes
2
answers
370
views
Divisibility condition implies $a_1=\dotsb=a_k$?
Let $a_1, a_2, \dotsc, a_k$ be $k$ positive integers, $k\ge2$. For all $n\ge n_0$ there is a positive integer $f(n)$ such that $n$ and $f(n)$ are relatively prime and $a_{1}^{f(n)}+\dotsb+a_{k}^{f(n)} …
10
votes
0
answers
188
views
Permutation of positive integers
Let $a_n$ be a sequence such that $a_1=1$ and for each $n \geq 1$ $a_{n+1}$ is the smallest positive integer distinct from $a_1,a_2,...,a_n$ such that $\gcd(a_{n+1}a_n+1,a_i)=1$ for each $i=1,2,...,n …
6
votes
0
answers
469
views
(In)finitely many natural numbers are not the sum or difference of two perfect powers
Are there infinitely many positive integers which are neither a sum nor a difference of
two perfect powers?
This question was proposed some years ago at KoMaL.
It's easy to see that the odd nu …
4
votes
1
answer
271
views
$n$ variables Diophantine
Let $n \ge 2$ be a positive integer. Do there exist $n$ non-zero distinct integers such that the sum of their square is a perfect square and their product is a nth power?
For $n=2$ the answer is no, b …
4
votes
1
answer
200
views
$2$-adic order bound for $P(x)$
Let $P(x) \in \mathbb{Z}[x]$ be a monic polynomial of degree $n$, with no integer roots, such that $\upsilon_2(P(m))$ can assume $n$ different positive values, where $m \in \mathbb{Z}$ and $\upsilon_ …
3
votes
0
answers
198
views
On the equation $x^3+y^3+z^3-2xyz=N$
The following question was asked at MSE without any solution:
Show that the equation $x^3+y^3+z^3-2xyz=1$ have infinitely many integer solutions $(x,y,z)$.
A more general question was also propo …
3
votes
1
answer
193
views
Are there infinitey many $n$ dividing $\epsilon_11^n + \epsilon_22^n + \cdots + \epsilon_kk^n$?
Let $k>1$ be a positive integer.
Question 1. Does there exist infinitely many positive integers $n$ such that $$n \, | \, (1^n + 2^n + \cdots + k^n)?$$
And, more generally:
Question 2. Does there e …
3
votes
0
answers
272
views
Infinitely many $n$ such that $\gcd(\lfloor n\sqrt{2}\rfloor, \lfloor n\sqrt{3}\rfloor)=m$
Is it true that for any positive integer $m$ there are infinitely many positive integers $n$ such that $\gcd(\lfloor n\sqrt{2}\rfloor, \lfloor n\sqrt{3}\rfloor)=m$?
$\lfloor x \rfloor$ is the floor …
3
votes
0
answers
131
views
Number of divisors of $2^k+1$
Let $p_1,p_2,\ldots,p_n$ be distinct primes greater than $3$ and $k=p_1p_2 \ldots p_n$. It is a known result that $2^{k}+1$ has at least $4^n$ divisors (this was a shortlisted problem from IMO 2002 - …
2
votes
1
answer
317
views
Divisors of a quadratic trinomial
Let $P(n)$ be a quadratic trinomial with integer coefficients.
For each positive integer $n$, the number $P(n)$ has a proper divisor $d_{n}$
(i.e. $1 < d_{n} < P(n)$), such that the sequence $ …
1
vote
1
answer
369
views
Construction of an irreducible polynomial on $\mathbb{Z}[x]$
Given a positive integer $m>1$, prove that there exists a polynomial of integer coefficients $P(x)$ that is irreducible on $\mathbb{Z}[x]$, has degree $2018$ and has a real root $r$ satisfying $m \mi …