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1 vote

Mitchell's embedding theorem

EDIT: I'm completely rewriting this in detail now that I think I've worked it out. Lots of possibilities for mistakes here, so stay alert! I claim that the generalization to include $(a)$ fails. My c …
Dylan Wilson's user avatar
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35 votes

Abelian category equivalent to a non-abelian category

Here is a manifestly invariant definition of an abelian category $\mathcal{C}$. It is a category with finite limits and colimits such that: (It is pointed) the map from the initial to the final obje …
Dylan Wilson's user avatar
  • 13.5k
9 votes

how to make the category of chain complexes into an $(\infty,1)$-category

I don't know what 'explicit' means, but this is all covered in Higher Algebra very well. If you want a simplicial category at the end of the day, you can either... Take your favorite $\infty$-categ …
Dylan Wilson's user avatar
  • 13.5k