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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.
7
votes
Synthetic vs. classical differential geometry
You might also find the work of Joyce useful, which builds upon the work of Dubuc (E. J. Dubuc. C∞-schemes. Amer. J. Math., 103(4):683–690, 1981) and Moerdijk and Reyes (I. Moerdijk and G. E. Reyes. M …
3
votes
0
answers
515
views
"Step-by-Step" toric resolution process?
WLOG the fan $\Sigma$ of our toric variety $X_{\Sigma}$ is simplicial. (So $X_{\Sigma}$ has at worst orbifold singularities and all cones $\sigma \in \Sigma$ are simplicial).
The classical toric reso …
15
votes
2
answers
1k
views
When do blowups ''commute''?
Let $M$ be a manifold (variety, scheme, your favorite object) and let $N_1,N_2$ be two submanifolds (subvarieties, closed subschemes, ideal sheafes, etc.) such that $N_1 \cap N_2 \neq \emptyset$. Deno …
0
votes
1
answer
1k
views
Zero locus of a generic smooth section
Let $V$ be a smooth manifold, $E \rightarrow V$ a vector bundle over $V$ and $\Gamma$ be a finite group acting nontrivially on $V$ and $E$. Let $s \in C^\infty(E)$ be a generic $\Gamma$-equivariant se …
3
votes
Riemannian Geometry
Just to add some things to Igor Belegradek's post:
"1.That the isometry group of a Riemannian manifold is always a lie group."
This is the famous Myers-Steenrod theorem, proven in 1939 (Myers, S.B. a …
9
votes
4
answers
2k
views
Cotangent bundle of a submanifold
Maybe this is a silly question (or not even a question), but I was wondering whether the cotangent bundle of a submanifold is somehow canonically related to the cotangent bundle of the ambient space.
…
2
votes
Undergraduate differential geometry texts
I'm not sure whether the following is too advanced, but I found
"Introduction to Topological Manifolds (Graduate Texts in Mathematics) (Paperback) by John Lee"
quite readable.
(Edit: As Ho Chung Si …
3
votes
Indexing the line bundles over a Grassmannian.
First of all: this is from the "differential-geometric point of view"
If you want to "classify" vector bundles chern classes are a very helpful tool. Well, it can happen that two bundles are "differe …
58
votes
10
answers
9k
views
de Rham cohomology and flat vector bundles
I was wondering whether there is some notion of "vector bundle de Rham cohomology".
To be more precise: the k-th de Rham cohomology group of a manifold $H_{dR}^{k}(M)$ is defined as the set of closed …
3
votes
Global proof of Serre duality
Since a $\bar{\partial}$-Operator is an elliptic Operator, you can use elliptic theory in order to prove the Serre duality. In fact the Serre duality is a kind of corollary of the"fundamental theorem" …
9
votes
1
answer
772
views
Infinite dimensional Newlander-Nirenberg theorem
The Newlander-Nirenberg theorem states that an almost complex structure is integrable if and only if the Nijenhuis tensor vanishes.
I heard that this statement is not true in infinite dimensions, sin …