Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 675

Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

7 votes

Synthetic vs. classical differential geometry

You might also find the work of Joyce useful, which builds upon the work of Dubuc (E. J. Dubuc. C∞-schemes. Amer. J. Math., 103(4):683–690, 1981) and Moerdijk and Reyes (I. Moerdijk and G. E. Reyes. M …
Spinorbundle's user avatar
  • 1,939
3 votes
0 answers
515 views

"Step-by-Step" toric resolution process?

WLOG the fan $\Sigma$ of our toric variety $X_{\Sigma}$ is simplicial. (So $X_{\Sigma}$ has at worst orbifold singularities and all cones $\sigma \in \Sigma$ are simplicial). The classical toric reso …
Spinorbundle's user avatar
  • 1,939
15 votes
2 answers
1k views

When do blowups ''commute''?

Let $M$ be a manifold (variety, scheme, your favorite object) and let $N_1,N_2$ be two submanifolds (subvarieties, closed subschemes, ideal sheafes, etc.) such that $N_1 \cap N_2 \neq \emptyset$. Deno …
Spinorbundle's user avatar
  • 1,939
0 votes
1 answer
1k views

Zero locus of a generic smooth section

Let $V$ be a smooth manifold, $E \rightarrow V$ a vector bundle over $V$ and $\Gamma$ be a finite group acting nontrivially on $V$ and $E$. Let $s \in C^\infty(E)$ be a generic $\Gamma$-equivariant se …
Spinorbundle's user avatar
  • 1,939
3 votes

Riemannian Geometry

Just to add some things to Igor Belegradek's post: "1.That the isometry group of a Riemannian manifold is always a lie group." This is the famous Myers-Steenrod theorem, proven in 1939 (Myers, S.B. a …
Spinorbundle's user avatar
  • 1,939
9 votes
4 answers
2k views

Cotangent bundle of a submanifold

Maybe this is a silly question (or not even a question), but I was wondering whether the cotangent bundle of a submanifold is somehow canonically related to the cotangent bundle of the ambient space. …
Spinorbundle's user avatar
  • 1,939
2 votes

Undergraduate differential geometry texts

I'm not sure whether the following is too advanced, but I found "Introduction to Topological Manifolds (Graduate Texts in Mathematics) (Paperback) by John Lee" quite readable. (Edit: As Ho Chung Si …
3 votes

Indexing the line bundles over a Grassmannian.

First of all: this is from the "differential-geometric point of view" If you want to "classify" vector bundles chern classes are a very helpful tool. Well, it can happen that two bundles are "differe …
Spinorbundle's user avatar
  • 1,939
58 votes
10 answers
9k views

de Rham cohomology and flat vector bundles

I was wondering whether there is some notion of "vector bundle de Rham cohomology". To be more precise: the k-th de Rham cohomology group of a manifold $H_{dR}^{k}(M)$ is defined as the set of closed …
Spinorbundle's user avatar
  • 1,939
3 votes

Global proof of Serre duality

Since a $\bar{\partial}$-Operator is an elliptic Operator, you can use elliptic theory in order to prove the Serre duality. In fact the Serre duality is a kind of corollary of the"fundamental theorem" …
Spinorbundle's user avatar
  • 1,939
9 votes
1 answer
772 views

Infinite dimensional Newlander-Nirenberg theorem

The Newlander-Nirenberg theorem states that an almost complex structure is integrable if and only if the Nijenhuis tensor vanishes. I heard that this statement is not true in infinite dimensions, sin …
Spinorbundle's user avatar
  • 1,939