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Enriched categories, topoi, abelian categories, monoidal categories, homological algebra.
1
vote
Splitting lemma under assumption of the axiom of choice
This is right: a map $f:A \rightarrow B$ is surjectiv $\Longleftrightarrow$ $f$ has a right-inverse. The proof needs the axiom of choice, as you pointed out correctly. But this is just a map of sets.
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7
votes
Synthetic vs. classical differential geometry
You might also find the work of Joyce useful, which builds upon the work of Dubuc (E. J. Dubuc. C∞-schemes. Amer. J. Math., 103(4):683–690, 1981) and Moerdijk and Reyes (I. Moerdijk and G. E. Reyes. M …