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Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
2
votes
Inner product on $V_{-\rho}$?
I'm not totally sure what will satisfy you on this account. Of course you pointedly restricted yourself to the reals, but some complex manifolds do have holomorphic half-form bundles, and the flag ma …
5
votes
Accepted
Kazhdan-Lusztig C-basis and categorification
If you identify the Hecke algebra with the Grothendieck principal block of a graded lift of category $\mathcal{O}$ for the corresponding semi-simple Lie algebra (oddly, enough which of the two Langlan …
3
votes
How can we describe the splitting of nilpotent orbit for "very even" partitions in the speci...
I don't have a full answer, or a good reference, but here's how I think one should answer the question:
By Jacobson-Morozov (see Chriss & Ginzburg for more details), classifying nilpotents in a semi- …
2
votes
Explicit computations of small Deligne-Lusztig varieties (e.g. Drinfeld curve)
This is all on the wikipedia page for Deligne-Lusztig theory.
I don't recognize the definition that you give, and can't see why it should be equivalent to the one I know. I'm not sure it's wrong, si …
1
vote
Conjugacy classes of reductive groups defined over local commutative rings
I don't have a complete answer or a reference, but I have a principle:
(*) a conjugacy class in GL(n) is the same as an isomorphism class of n-dimensional representation of $\mathbb{Z}$.
Similarly, …
4
votes
Accepted
Is there an easy way to find the minimum dimensions of representations for these R-algebras?
Yes. These can be proven by some very simple principles.
The smallest representation of a division ring is the ring itself (this covers the first 3), since it has no left or right ideals.
When yo …
1
vote
A general theory of multiplicity-free actions of $G\times H$?
Well, one "general" theorem is
If A and B are semi-simple algebras acting faithfully on a finite dimensional vector space $V$ such that $\mathrm{End}_A(V)=B$ and vice versa, then tensoring with $ …
9
votes
Accepted
Questions about Quivers
The short answer is no. You just have to think of them as formal sums, in the same way that you can only think of elements of a group algebra as formal sums.
What you can do is think of the path cat …
3
votes
Accepted
Character theory over integers
The isomorphism works over Z. The proof is that the basis change between W-symmetrized monomials and characters is upper-triangular with 1's on the diagonal.
3
votes
Springer corresponding for nullcones other than the standard nilpotent cone
Certainly, there's no reason to believe there will be. The Springer correspondence depends very strongly on the existence and structure on the Springer resolution.
2
votes
Accepted
A bijection between "symplectic" partitions and bi-partitions via Springer correspondance
From looking at the slides, it sure looks like you wrote it in your answer: take 2-quotients.
I'm not sure if there's a standard reference for n-quotients of partitions, but they're described in this …
12
votes
Accepted
Gabriel's theorem over a commutative ring
Certainly it doesn't generalize in a really obvious way. One way to think about this is the following: Gabriel's theorem uses in really deep way that the category of quiver representations over a fi …
3
votes
How to think about parabolic induction.
Not an answer, but here's a rephrasing: this question is equivalent to asking why parabolic restriction doesn't depend on the parabolic (parabolic restriction is the adjoint, so you restrict to the pa …
25
votes
Accepted
A learning roadmap for Representation Theory
I second the suggestion of Fulton and Harris. It's a funny book, and definitely you want to keep going after you finish it, but it's a good introduction to the basic ideas.
You specifically might be …
4
votes
Sum of product of characters of $S_{n+m}$ over $S_n$
I would rather write $\chi_{R_1}(a)=\chi_{R_1^*}(a^{-1})$. This allows us to see the sum
$$\frac{1}{n!}\sum_{a\in S_n}\chi_{R_1^*}(a^{-1})\chi_{R_2}(ba)$$ as the trace on $\mathrm{Hom}_{\mathbb{C}}(R …