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4
votes
Accepted
The evaluation and coevaluation maps for an object isomorphic to a dualisable object
This won't fit in a comment, maybe it's useful to someone:
$$ \begin{align*}
(\mathrm{id}_Y⊗\mathrm{ev}_Y)∘(\mathrm{coev}_Y⊗\mathrm{id}_Y) &=
(\mathrm{id}_Y⊗\mathrm{ev}_X)∘(\mathrm{id}_{Y⊗X^*}⊗σ^{-1} …