Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 61536

A poset or partially ordered set is a set endowed with a partial order, meaning a binary relation $\leq$ which is reflexive ($x \leq x$ for all $x$), antisymmetric ($x\leq y$ and $y\leq x$ implies $x=y$), and transitive ($x\leq y$ and $y\leq z$ implies $x \leq z$).

1 vote
Accepted

Thinning directed sets ${\frak P}$ of partitions of $\omega$ with no ${\frak P}$-discrete su...

The answer to this question is negative. Given a linearly ordered family $\mathfrak C$ of finitary partitions of $\omega$, write $\mathfrak C=\bigcup_{n=1}^\infty\mathfrak C_n$ where $\mathfrak C_n=\{ …
Taras Banakh's user avatar
  • 41.8k
2 votes
Accepted

Is there some characterization of $\omega^\omega$-base related to $S_\omega$?

This question has negative answer. To construct a counterexample, consider the set $X=(\omega\times\omega)\cup\{\infty\}$ where $\infty\notin(\omega\times\omega)$ is any point. Then set $X$ is endowe …
Taras Banakh's user avatar
  • 41.8k
4 votes
Accepted

Order convergence vs topological convergence in partially ordered sets

The answer to this question is negative. As a counterexample, consider the one-point extension $P:=2^{<\omega}\cup\{\infty\}$ of the binary tree $2^{<\omega}=\bigcup_{n\in\omega}2^n$. Here $2$ is the …
Taras Banakh's user avatar
  • 41.8k
6 votes
Accepted

$\text{Max}\big(\text{Sub}(\text{Sym}(\omega))\setminus \{\text{Sym}(\omega)\}\big)$

As was written by Andreas Thom in his comment, Google gives an extensive literature on this subject. For example, look at the papers https://link.springer.com/chapter/10.1007/978-94-011-2080-7_18 or h …
Taras Banakh's user avatar
  • 41.8k
2 votes
Accepted

Maximal elements in the partially ordered set of image spaces

A positive answer to this problem is given by the known answers to the following problem posed by de Groot in New Scottish book. Problem 393 (de Groot; 28 May, 1958). Does there exist a (plane) conti …
Taras Banakh's user avatar
  • 41.8k
3 votes
Accepted

Minimal Hausdorff topologies compatible with a bunch of functions

The answer to this question is affirmative: Theorem. There exists a countable set $X$ and an uncountable family $\mathcal F$ of self-functions of $X$ such that the poset $T_2(\mathcal F)$ has no min …
Taras Banakh's user avatar
  • 41.8k
1 vote
Accepted

Compactification of order-disconnected spaces

It seems that the answer to this problem is affirmative: Take a well-behaved pospace $P$. To show that $\beta_2(P)$ is well-behaved, take any clopen upper set $U\subset \beta_2(P)$. We should prove t …
Taras Banakh's user avatar
  • 41.8k
4 votes
Accepted

Topologies with no minimal $T_2$ topologies above them

There exists a topology $\tau$ with two non-isolated points on a countable set $X$ such that the poset $T_2(\tau)$ does not have minimal elements. To construct such topology $\tau$, take any Hausdorf …
Taras Banakh's user avatar
  • 41.8k
2 votes
Accepted

Spaces that are invariant under some contractions

For a countable space $X$ the discussed property means that $X$ is homeomorphic to $X/A$ for any finite subset $A\subset X$. Let us call this property quotient-homogeneous. There are many quotient-h …
Taras Banakh's user avatar
  • 41.8k