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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions

1 vote
1 answer
159 views

The existence of solutions of a Diophantine exponential equation

Given a prime number $p$ and a positive integer $n$, I am interested in the (non)existence of positive integer solutions $x,x_0,\dots,x_{p^n}$ of the following Diophantine equation $$p^x+p^n=\sum_{i=0 …
9 votes
0 answers
223 views

Who was the first to prove that the automorphism group of a finite field is cyclic and is ge...

$\DeclareMathOperator\Aut{Aut}$It is well-known that the automorphism group $\Aut(F)$ of a finite field $F$ of characteristic $p$ is cyclic of order $n$ where $|F|=p^n$. Moreover, the cyclic group $\A …
1 vote

Collecting proofs that finite multiplicative subgroups of fields are cyclic

There is a quite elementary proof that uses only the fact that a polynomial of degree $n$ has at most $n$ roots in a field. So, let $F$ be a field and $G$ be a finite subgroup of the multiplicative gr …
Taras Banakh's user avatar
  • 41.8k
5 votes
2 answers
264 views

Diophantine equation $x^p+ax=y^p+by$

Problem. Is there a prime number $p$ (desirably $p\le 3$) and an infinite set $A\subset\mathbb N$ such that for any distinct numbers $a,b\in A$ the Diophantine equation $x^p+ax=y^p+by$ has no positive …
3 votes
0 answers
180 views

Is there any analogue of $\pi$ for non-Archimedean Euclidean fields?

Let us recall that a Euclidean field is an ordered field in which every positive element has a square root. Given a Euclidean field $F$, we can consider the ``Euclidean'' plane $F^2$ endowed with the …
5 votes
1 answer
357 views

The number of polynomials on a finite group, II

This question is follow up of this MO-post. First let us recall the necessary definitions. A function $f:X\to X$ on a group $X$ is called a polynomial if there exists $n\in\mathbb N$ and elements $a_0 …
5 votes
0 answers
263 views

Are continuous self-maps of the Golomb space $\mathbb G$ dense in the space of all self-maps...

The Golomb space $\mathbb G$ is the set $\mathbb N$ of positive integers endowed with the topology generated by the base consisting of arithmetic sequences $a+b\mathbb N_0:=\{a+bn:n\ge 0\}$ with $a,b$ …
29 votes
1 answer
1k views

Is the Golomb countable connected space topologically rigid?

The Golomb space $\mathbb G$ is the set of positive integers endowed with the topology generated by the base consisting of the arithmetic progressions $a+b\mathbb N_0$ with relatively prime $a,b$ and …
22 votes
Accepted

Is the Golomb countable connected space topologically rigid?

[Edit, Dec 6, 2019] I have a pleasure to inform that this problem was finally resolved in affirmative by T.Banakh, D.Spirito and S.Turek who proved the following Theorem. The Golomb space is topologi …
YCor's user avatar
  • 63.9k
11 votes
2 answers
1k views

The Fibonacci sequence modulo $5^n$

Let $(F_k)_{k=0}^\infty$ be the classical Fibonacci sequence, defined by the recursive formula $F_{k+1}=F_k+F_{k-1}$ where $F_0=0$ and $F_1=1$. For every $n\in\mathbb N$ let $\pi(n)$ be the smallest p …
2 votes
1 answer
344 views

Are half of the $2^n$-th roots of the unit rationally independent?

The following question was motivated by this MO-post. I hope that the answer should be known to experts (because of very simple formulation)... Problem. Let $n\ge 2$. Is the set of complex numbers $\ …
5 votes
2 answers
510 views

A modern reference to the Zsigmondy Theorem

I need to cite the classical Zsigmondy Theorem, which was proved in 1892. Is there any modern reference to this theorem? I mean some standard textbook in Number Theory containing this theorem together …
18 votes

Dividing a cake between $n-1$, $n$, or $n+1$ guests

Writing down the details of the argument of Ilya Bogdanov, we can obtain the following upper bound: Theorem. $f(n)\le\frac83n-1$ for every $n\ge 2$. Proof. If $n=3k+1$ or $n=3k+2$, then following th …
Taras Banakh's user avatar
  • 41.8k
9 votes
1 answer
684 views

Strange and non-strange prime numbers, are there infinitely many of them?

Definition. A prime number $p$ is called strange if there exists $k>1$ such that each prime divisior of $p^k-1$ divides $p-1$. Example 3. The prime number $p=3$ is strange as $3^2-1=8$ has the same pr …
7 votes
1 answer
296 views

The density of the set of non-pathological primes

An prime number $p$ is called pathological if there exists a prime number $q\ne p$ such that for every $n\in\mathbb N$ the number $2^n-1$ is divisible by $p$ if and only if $2^n-1$ is divisible by $q$ …

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