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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
2
votes
2
answers
124
views
A contractible non-planar continuum
Let $Z=\{0\}\cup\{\pm\frac1n\}_{n\in\mathbb N}$ be the sequence that converges to zero from both sides. Consider the contractible continuum $$A=(Z\times[-1,1]\times\{0\})\cup([-1,1]\times\{0\}\times\{ …
7
votes
1
answer
243
views
Characterizing topological spaces $X,Y$ whose function space $C_k(X,Y)$ is Baire
I am looking for a characterization of topological spaces $X,Y$ for which the function space $C_k(X,Y)$ is Baire. Here $C_k(X,Y)$ is the space of continuous functions from $X$ to $Y$, endowed with th …
4
votes
0
answers
50
views
The normality of powers versus the normality hypersymmetric powers
Let $X$ be a topological space. Let $[X]^{<\omega}$ be the space of non-empty finite subsets of $X$, endowed with the Vietoris topology. For a natural number $n$ the subspace $$[X]^{\le n}:=\{A\in[X]^ …
8
votes
2
answers
345
views
Are almost sequential spaces sequential?
A topological space $X$ is called
$\bullet$ sequential if for each non-closed subset $A\subset X$ there exists a sequence $\{a_n\}_{n\in\omega}\subset A$ that converges to a point $a\notin A$;
$\bu …
0
votes
1
answer
231
views
Does every compact countable space contain a non-trivial convergent sequence?
Problem. Does every compact countable space contain a non-trivial convergent sequence?
This question concerns non-Hausdorff compact spaces. An example of such space is any infinite set $X$ endowed wi …
5
votes
1
answer
180
views
Which compacta contain copies of Cantor cubes?
It is well-known that each uncountable compact metrizable space $X$ contains a homeomorphic copy of the Cantor cube $\{0,1\}^\omega$. What about copies of Cantor cubes of larger weight?
Problem. Does …
2
votes
0
answers
143
views
How to unify these three classes of topological spaces?
For a cardinal $\kappa$ let $\Box^\kappa\mathbb R$ be the box-product of $\kappa$-many lines and $\boxdot^\kappa\mathbb R:=\{x\in\Box^\kappa:|\{\alpha\in\kappa:x(\alpha)\ne 0\}<\omega\}$ be the $\sigm …
2
votes
0
answers
65
views
Two questions about subsequential spaces with countable $k$-network
This question was motivated by my answer to this MO question, which asked about the characterization of spaces that belong to the smallest class of topological spaces that is closed under taking subsp …
2
votes
0
answers
76
views
A possible characterization of stratifiable spaces?
Let us recall that a regular topological space is semi-stratifiable if each point $x\in X$ has a countable family of neighborhoods $(U_n(x))_{n\in\omega}$ such that each closed subset $F\subset X$ is …
2
votes
0
answers
42
views
Is each zero-dimensional cometrizable space zero-cometrizable?
A topological space $X$ is defined to be
$\bullet$ cometrizable if $X$ admits a weaker metrizable topology $\tau$ such that for every point $x\in X$ and a neighborhood $U_x\subseteq X$ of $x$ there e …
2
votes
0
answers
81
views
Is every first-countable symmetrizable space perfect?
Let us recall that a symmetric on a set $X$ is any function $d:X\times X\to[0,\infty)$ such that
for every $x,y\in X$ the following two conditions are satisfied:
$d(x,y)=0$ if and only if $x=y$;
$d( …
4
votes
0
answers
72
views
Is each typical map on the $n$-cube strongly rigid?
This question is inspired by this (still unanswered) MO-post.
A function $f:X\to Y$ between topological spaces is called strongly rigid if every continuous self-map $h:X\to X$ with $f\circ h=f$ is the …
9
votes
1
answer
383
views
New separation axiom?
I am looking for the name and notation of the following separation axiom , temporarily denoted by $T_i$ (where $i=\sqrt{-1}$ is the imaginary unit):
Axiom $T_i$: For any point $x$ of a topological sp …
1
vote
1
answer
331
views
Convergent sequences in compact spaces
Problem. Assume that a compact space $X$ can be written as the union $X=K\cup D$ of a compact metrizable subspace $K$ and a discrete subspace $D$.
Does $D$ contain a non-trivial convergent sequence in …
8
votes
1
answer
707
views
Is every second-countable Hausdorff space symmetrizable?
Let us recall that a symmetric on a set $X$ is any function $d:X\times X\to[0,\infty)$ such that
for every $x,y\in X$ the following two conditions are satisfied:
$\bullet$ $d(x,y)=0$ if and only if $x …