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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
13
votes
Is every connected subgroup of a Euclidean space closed?
A small amendment of the result of Hidehiko mentioned in the answer of Moishe Kohan: Theorem 2.2 in this paper implies that every continuum-connected subgroup of $\mathbb R^n$ is a (closed) linear sub …
2
votes
1
answer
131
views
The separability of superextensions
The superextension $\lambda X$ of a compact Hausdorff space $X$ is the space of maximal linked systems of closed subsets of $X$, endowed with the Vietoris topology inherited from the double hyperspace …
6
votes
1
answer
538
views
Does Playfair imply Proclus?
I am interested in the interplay between the Playfair and Proclus Axioms in linear spaces.
By a linear space I understand a pair $(X,\mathcal L)$ consisting of a set $X$ and a family $\mathcal L$ of s …
2
votes
Accepted
Being contained in a compact set
It seems that Gutik's hedgehog is a required counterexample.
I recall that Gutik's hedgehog is the set $$X=\{(0,0)\}\cup\{(\tfrac1n,0):n\in\mathbb N\}\cup\{(\tfrac1n,\tfrac1{nm}):n,m\in\mathbb N\}$$
e …
2
votes
Accepted
Constructing a continuous function with a prescribed preimage
Open sets with the required property are exactly functionally open sets.
Let us recall that a subset $U$ of a topological space $X$ is functionally open in $X$ if $U=f^{-1}[V]$ for some continuous fun …
2
votes
A generic metric on $X\cup\mathbb Z$
The affirmative answer to this problem follows from a general result on extension of graph metrics. In the following definitions, the unordered pair $\{x,y\}$ of two elements $x,y$ is denoted by $xy$. …
1
vote
Accepted
The continuity of certain maps on compact Hausdorff spaces
The answer to this question is affirmative.
Proposition. Let $p:X\to Y$ be a proper bijective map from a Hausdorff topological space $X$ onto a $T_1$-space $Y$. Then for every continuous map $f:K\to …
11
votes
Accepted
Does a completely metrizable space admit a compatible metric where all intersections of nest...
Let us say that a topological space $X$ is spherically completely metrizable if the topology of $X$ is generated by a spherically complete metric.
Theorem. Every closed subspace $X$ of the countable …
7
votes
2
answers
644
views
A generic metric on $X\cup\mathbb Z$
$\newcommand\abs[1]{\lvert#1\rvert}$Let $(X,d_X)$ be a countable metric space such that $X\cap\mathbb Z=\{0\}$.
Problem. Is there a metric $d$ on the union $Y=X\cup\mathbb Z$ such that
$d(x,y)=d_X(x, …
6
votes
1
answer
491
views
A characterization of metric spaces, isometric to subspaces of Euclidean spaces
I am looking for the reference to the following (surely known) characterization of metric spaces that embed into $\mathbb R^n$:
Theorem. Let $n$ be positive integer number. A metric space $X$ is isom …
5
votes
1
answer
164
views
What structure is preserved by pseudo-homeomorphisms of pseudo-Euclidean spaces?
Let us recall that for integer numbers $t,s\ge 0$ the pseudo-Euclidean space $\mathbb R^{t,s}$ is the vector space $\mathbb R^{t+s}$ endowed with the quadratic form $q_{t,s}:\mathbb R^{t+s}\to\mathbb …
6
votes
1
answer
223
views
The continuity of certain maps on compact Hausdorff spaces
Let $f:M\to Y$ be a continuous proper bijective map from a metrizable space $M$ onto a $T_1$-space $Y$. The properness of $f$ means that for every compact subspace $K\subseteq Y$ the preimage $f^{-1}[ …
11
votes
Accepted
Space with compactly closed diagonal but which is not weak Hausdorff
The space $X$ constructed in Theorem 1.5 of this preprint has the required properties. This space contains a non-closed compact metrizable subspace $K$, so is not weakly Hausdorff.
On the other hand, …
10
votes
Accepted
Under what conditions is the compact-open topology compactly generated?
Not necessarily: consider the compactly generated space $Y=\mathbb R^\infty=\varinjlim \mathbb R^n$, which is the direct limit of Euclidean spaces. Then for the countable discrete space $X=\omega$ th …
6
votes
Accepted
Continuous functions on $[0,1]^\omega$ and a product lower bound
The second question also has the negative answer:
Take any sequence $z=(z_n)_{n\in\omega}\in[0,1]^\omega$ with $f(z)=0$. On the Hilbert cube $[0,1]^\omega$, consider the metric $d(x,y)=\max_{n\in\omeg …