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Prime numbers, diophantine equations, diophantine approximations, analytic or algebraic number theory, arithmetic geometry, Galois theory, transcendental number theory, continued fractions
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On primes of the form 2^n + k [duplicate]
For any odd number $k$, can we always find an $n$ so that $2^n > k$ and $2^n + k$ is a prime number?
Any comment or remark is welcomed!
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Generating function for numbers divisible by some primes
Consider the first $k$ primes $p_1 = 2, p_2 = 3, \dots, p_k$. Let $A_k$ be the set of numbers that are divisible by at least one $p_i$. We can represent this set as a generating function:
$$G_k(x) = …