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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.

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$y^3=x^4+x$, and computing all rational points on rank $0$ Picard curves

Let $x = \frac{a}{d}$, $y = \frac{b}{d}$, $\gcd(a, d, b) = 1$. $$b^3d = a^4 + ad^3$$ Suppose $p \mid a$ and $p \mid d$ for prime $p$. Then $b$ is not divisible by $p$. $$\nu_p(d) = \nu_p(a^4 + ad^3) …
Denis Shatrov's user avatar