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Homotopy theory, homological algebra, algebraic treatments of manifolds.

56 votes

understanding Steenrod squares

Here's how I explain Steenrod squares to geometers. First, if $X$ is a manifold of dimension $d$ then one can produce classes in $H^n(X)$ by proper maps $f: V \to X$ where $V$ is a manifold of dimens …
Dev Sinha's user avatar
  • 4,990
40 votes

Why does one think to Steenrod squares and powers?

Here's how I explain Steenrod squares to geometers. First, if $X$ is a manifold of dimension $d$ then one can produce classes in $H^n(X)$ by proper maps $f: V \to X$ where $V$ is a manifold of dimens …
Dev Sinha's user avatar
  • 4,990
33 votes

"Why the heck are the homotopy groups of the sphere so damn complicated?"

You're going to get many different answers depending on the tastes of the topologist answering... I like to think about homotopy groups of spheres through framed cobordism. Theories like unoriented …
22 votes
Accepted

Advantages of working with CW complexes/spaces over Kan complexes/simplicial sets?

I think there are many times that simplicial sets are preferable (e.g for classifying spaces the simplicial construction is often advantageous), but to answer the stated question: CW complexes conne …
19 votes

Modern survey of unstable homotopy groups?

Behrens's monograph "The Goodwillie tower and the EHP sequence" reproduces some of the Toda calculations (out to the k~20 range as you cite) using a modern toolset, as named in the title. Depending o …
Dev Sinha's user avatar
  • 4,990
19 votes
2 answers
1k views

Geometric model for classifying spaces of alternating groups

The classifying space of the nth symmetric group $S_n$ is well-known to be modeled by the space of subsets of $R^\infty$ of cardinality $n$. Various subgroups of $S_n$ have related models. For examp …
Dev Sinha's user avatar
  • 4,990
16 votes

How to get product on cohomology using the K(G, n)?

Yes, this iterated bar construction model should be better known, and can be expressed even more geometrically than Ravenel and Wilson do. If $A$ is an abelian group then $K(A,n)$ is modeled by a spa …
Dev Sinha's user avatar
  • 4,990
15 votes

What is the intuition for higher homotopy groups not vanishing?

Homotopy groups of spheres correspond to framed submanifolds of Euclidean space through the Pontrjagin-Thom construction. For example, the Hopf map corresponds to a circle in $\mathbb{R}^3$ framed “w …
Dev Sinha's user avatar
  • 4,990
15 votes
1 answer
495 views

Geometric models for classifying spaces of $GLn(Fq)$.

The title pretty much says it. In a follow-up to my question about alternating groups, does anyone know of a "geometric" model for $BGL_n(F_q)$? By "geometric" I mean "a space you would have heard a …
Dev Sinha's user avatar
  • 4,990
14 votes
2 answers
1k views

Dyer-Lashof based spectral sequence for homotopy classes of maps between infinite loop space...

The homology of an infinite loop space, which represents a spectrum, is an algebra over the Dyer-Lashof algebra (see for example Cohen-Lada-May's Springer volume, or for part of the story the more acc …
Dev Sinha's user avatar
  • 4,990
13 votes

Detailed proof of cup product equivalent to intersection

Bott and Tu do this completely, in the de Rham theoretic setting of course. Here's an alternate proof I have used when I teach this material, which I find slightly more clean and direct than using Tho …
Dev Sinha's user avatar
  • 4,990
12 votes

Homotopy commutativity of the cup product

These operations in the singular setting were fully and explicitly developed and generalized beautifully by McClure and Smith (who also credit Benson and Milgram) in their paper "Multivariable cochain …
Dev Sinha's user avatar
  • 4,990
12 votes

Construction of the Stiefel-Whitney and Chern Classes

Let me offer another definition not far from obstruction theory (as Ilya gave), but without referring to obstruction theory and thus more elementary. Suppose for simplicity that $X$ is a simplicial c …
Dev Sinha's user avatar
  • 4,990
12 votes

Why aren't there more classifying spaces in number theory?

As a topologist, my view is that group cohomology of interest to number theorests seems to generally be with non-trivial module coefficients. Many of the tricks topologists employ to study spaces do …
Dev Sinha's user avatar
  • 4,990
11 votes
1 answer
564 views

The space of compact subspaces of $R^\infty$ homotopy equivalent to a given finite complex.

Let $X$ be a finite (CW or simplicial - doesn't matter) complex and consider the space of all compact subspaces of $R^\infty$ which are homotopy equivalent to $X$, topologized say as a subspace of the …
Dev Sinha's user avatar
  • 4,990

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