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Cobordism is a fundamental equivalence relation on the class of compact manifolds of the same dimension, set up using the concept of the boundary of a manifold.

7 votes
1 answer
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What does Robert Stong mean when he says $H^*(MO(k))$ is a free Steenrod algebra in dimensio...

$\newcommand{\Z}{\mathbb Z}\newcommand{\a}{\mathfrak a}\newcommand\widetildeH{\smash{\widetilde H}}$In Robert Stong's notes on Cobordism Theory, on page 95 he asserts the following: $\widetildeH^* (MO …
Chris's user avatar
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2 votes
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An attempt at an alternative calculation of the rank of $\pi_n(MO)$

$\newcommand{\a}{\mathfrak a}\newcommand{\Z}{\mathbb Z}$Let $MO$ be the Thom Spectrum, then I am trying to come up with an alternative calculation that the rank of $\pi_n(MO)$ as a $\Z_2$ vector space …
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An attempt at an alternative calculation of the rank of $\pi_n(MO)$

$\newcommand{\a}{\mathfrak a}\newcommand{\Hom}{\operatorname{Hom}}\newcommand{\Z}{\mathbb Z}$ This can be proven by only assuming that $H^*(MO)$ is a free module. Indeed, due to $H^*(MO)$ being a grad …
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