Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with fa.functional-analysis
Search options not deleted
user 48144
Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
1
vote
Spectrum of operator defined by composition with linear function
This is really a comment, not an answer but I am not empowered. I am taking the liberty of reinterpreting your question (always a dangerous course) since it has already been pointed out that your ope …
- 334
4
votes
The derivative of a non-tempered distribution can be tempered?
A distribution is tempered if and only if it is the distributional derivative $D^nF$ of a continuous function $F$ which is $O(x^k)$ for some positive integer. Its primitive is then $D^{n-1}F$ and so …
- 334
4
votes
Tightness of Measures, Riesz Representation for locally compact spaces
The proper framework for your question is the so-called strict topology on the space of bounded continuous functions which was introduced for the case of a locally compact space by R.C. Buck in the 50 …
- 334
6
votes
Accepted
Fréchet-Kolmogorov compactness Theorem for Lp spaces on manifolds
The result you mention uses the algebraic structure of euclidean space since it involves a form of uniform approxability of the set and its translates. However, there are many criteria for compactne …
- 334
1
vote
A sufficient condition for a probability measure to have compact support
The answer in the second case is even easier. In order to avoid circularity, define the Stieltjes transform of a measure only on the complex plane minus the real axis . Then the measure has support …
- 334