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Algebraic and geometric theory of quadratic forms and symmetric bilinear forms, e.g., values attained by quadratic forms, isotropic subspaces, the Witt ring, invariants of quadratic forms, the discriminant and Clifford algebra of a quadratic form, Pfister forms, automorphisms of quadratic forms.

2 votes

Fricke Klein method for isotropic ternary quadratic forms

The same formal record. If we look for a parameterization not in 2 and in 3 option the problem can be solved quite simply. For the equation. $$aX^2+bY^2+cZ^2=dXY+eXZ+fYZ$$ If you know any solution …
individ's user avatar
  • 480
0 votes

Isotropic ternary forms

Not entirely clear where one detail which is not mentioned. Ternary quadratic form always amounts to a Pell equation. For example if you take a fairly simple equation. And set some conditions for the …
individ's user avatar
  • 480
1 vote

Isotropic ternary forms

The mention of another quadratic form. You can use the standard approach. In equation $$aX^2+bY^2+cZ^2=qXY+dXZ+tYZ$$ $a,b,c,q,d,t$ integer coefficients which specify the conditions of the proble …
individ's user avatar
  • 480
1 vote

Indefinite quadratic form universal over negative integers

Representation of a number we write. $$aX^2+bY^2=cZ^2+q$$ I think that the only way to record the desired polynomial is to use the solutions of any equation. $$ax^2+by^2=cz^2$$ Knowing the solutio …
individ's user avatar
  • 480
2 votes

Does the Diophantine equation $(x^2+ay^2)(u^2+bv^2) = p^2+cq^2$ admit a complete solution?

I think that this method of calculation it is necessary to separately draw. As I have repeatedly said formula in General looks pretty bulky. And still remain questions about the completeness of the …
individ's user avatar
  • 480
-2 votes

Does the Diophantine equation $(x^2+ay^2)(u^2+bv^2) = p^2+cq^2$ admit a complete solution?

Still not clear what you want. If you need a method, the method of finding solutions I have already in a previous post wrote. If regarding the parameterization. Then for the equation: $$(x^2+ay^2) …
individ's user avatar
  • 480
-2 votes

Does the Diophantine equation $(x^2+ay^2)(u^2+bv^2) = p^2+cq^2$ admit a complete solution?

Once these equations are referred to - it is necessary to write and solutions. For the equation: $$X_1^2+X_2^2=Y_1^2+Y_2^2+Y_3^2$$ Solutions have the form: $$X_1=t^2+2(p+s-k)t+2k^2+2p^2+4ps-4pk-2s …
individ's user avatar
  • 480
0 votes

On certain solutions of a quadratic form equation

For such quadratic forms. $$ax^2-bxy+cy^2=a$$ If we consider all the equations of Pell. The resulting factorization of the number. $4a=tq$ And use these equations Pell. $$p^2-(b^2-4ac)s^2=\pm{t}$ …
individ's user avatar
  • 480
-1 votes

Quadratic diophantine equations and geometry of numbers

It's more of a comment than an answer. Make such a change.... $x=X+q$ $$w^2-ax^2-by^2+abz^2=1$$ $$w^2-aq^2+abz^2=by^2+aX^2+2aqX+1$$ If we use this difference as Pell's equation. $w^2-aq^2=1$ Equ …
individ's user avatar
  • 480