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Nearly length minimizing paths are close to geodesics?

$\newcommand{\Im}{\operatorname{Image}}$ I am trying to construct a complete argument based on Pietro's suggestion: I assume $M$ is complete. Assume by contradiction the claim is false. Then there …
Asaf Shachar's user avatar
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3 votes
1 answer
209 views

Nearly length minimizing paths are close to geodesics? [closed]

It's known that length minimizing curves are geodesics (after a possible reparametrization). Now fix* points $p,q \in M$ Is the following assertion true? …
Asaf Shachar's user avatar
  • 6,741
4 votes
1 answer
432 views

Smooth manifolds for which every metric is geodesically convex

Are there non compact smooth manifolds which have the property that every Riemannian metric is geodesically convex? Note that a manifold for which every Riemannian metric is complete must be compact. …
Asaf Shachar's user avatar
  • 6,741
6 votes
1 answer
792 views

Totally geodesic subgroups in Lie groups

Since $g$ is bi-$H$-invariant, the geodesics of $H$ are the one-parameter subgroups of $H$. Hence, the question amounts to: Are the one-parameter subgroups of $H$ geodesics in $G$? …
Asaf Shachar's user avatar
  • 6,741
2 votes
1 answer
232 views

If any two triangles of equal area can be mapped via affine maps, what can we say about the ...

(equivalently, $f$ maps parametrized geodesics to parametrized geodesics. Here $\nabla=\nabla^{T^*M} \otimes \nabla^{f^*TM}$). …
Asaf Shachar's user avatar
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