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5 votes

What does the KL being symmetric tell us about the distributions?

We're looking at the equation $$-\sum_{x\in\mathcal{X}} P(x) \log\left(\frac{Q(x)}{P(x)}\right) = -\sum_{x\in\mathcal{X}} Q(x) \log\left(\frac{P(x)}{Q(x)}\right). $$ In the Bernoulli case, $$-p \log\ …
Bjørn Kjos-Hanssen's user avatar