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3
votes
Geometric proof of Robinson-Schensted-Knuth correspondence?
See "Une forme geometrique de la correspondance de Robinson–Schensted" by Viennot if you can read French. Otherwise, if I recall correctly it is in Sagan's book on the symmetric group.
5
votes
Implementation of the Robinson-Schensted correspondence
The Combinatorica package of Mathematica does it with the function PermutationToTableaux
p={1,3,6,4,7,5,2};
t=PermutationToTableaux[p];
t[[1]]//TableForm (* the P table *)
1 2 4 5
3 7
6
t[[2]]//Tab …