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3
votes
Convergence of Newton series for sin ax
weak discrete-analytic
Closed form here involves some ${}_2F_1$ functions, so I cannot provide proofs. Numerically, though, it seems that $\sin(ax)$ is weak discrete-analytic for $a$ up to some valu …
7
votes
Accepted
Convergence of Newton series for sin ax
half-discrete analytic
First do the formal calculation, then discuss its validity.
$$\begin{align}
&\sum_{m = 0}^{\infty} \binom{x}{m} \sum_{k = 0}^{m} \binom{m}{k} (-1)^{(m - k)} \operatorname{sin} …
33
votes
Accepted
What is the indefinite sum of tan(x)?
I add more details for the solution in the distinguished answer due to Anixx. First, we need the digamma function
http://en.wikipedia.org/wiki/Digamma_function
which we will call $\Psi(x)$. Importan …
6
votes
What is the indefinite sum of tan(x)?
There is no reason to think there is any simple expression for solution $T$ of
$$T(x + 1) - T(x) = \tan(x)$$
What we CAN find a simple solution to is this:
$$T(x + \pi) - T(x) = \tan(x)$$