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Complex, contact, Riemannian, pseudo-Riemannian and Finsler geometry, relativity, gauge theory, global analysis.

1 vote

Given an object in a Lie groupoid, does there exist a subgroupoid for which the object has n...

My gut would be no. Let us analyze what happens if this were to be true. Then, between any $z$,$w$ in the orbit of $x$, there is a unique arrow (since any two guys in the same orbit have isomorphic is …
David Carchedi's user avatar
6 votes

Defining Quotient Bundles

Let $h:E' \hookrightarrow E$ denote the inclusion of vector bundles. Let $p:Coker(h) \to B$ be defined in the obvious way (fiber at $x$ is $E_x/h(E'_x)$). It suffices to construct local trivialization …
David Carchedi's user avatar
12 votes
1 answer
535 views

Is every representable map a submersion?

Recall that a morphism $f:C \to D$ in a category $\mathscr{C}$ is representable if for all maps $g:E \to D$ in $\mathscr{C},$ the pullback $C \times_{D} E$ exists. Let now $\mathscr{C}$ be the catego …
David Carchedi's user avatar
3 votes
2 answers
341 views

Cohomology of the interior of a zero set of a smooth function

Given a smooth function $f:\mathbb{R}^n \to \mathbb{R},$ how much is known about the cohomology of the interior of the zero set $f^{-1}\left(0\right)$? I know this can be quite wild, e.g. this amounts …
David Carchedi's user avatar
12 votes
2 answers
783 views

Generalized smooth spaces and infinite dimensional manifolds

There is a theorem due to Losik which shows that the category of Frechet manifolds embeds fully-faithfully into diffeological spaces. (Diffeological spaces are concrete sheaves on the site of (Euclide …
David Carchedi's user avatar
9 votes

What is meant by smooth orbifold?

To be quick, just like manifolds, orbifolds have a fixed dimension. This does not vary point to point. This is also true of their tangent spaces. This is actually true for any etale differentiable sta …
David Carchedi's user avatar
3 votes

Smoothness of frame bundle of (global) orbifolds [reference request]

I recommend looking at Moerdijk and MrCun's "Introduction to Foliations and Lie Groupoids". On page 42, they define the frame bundle and orthonormal frame-bundle of an orbifold and show it's a smooth …
David Carchedi's user avatar
4 votes
Accepted

Co-completeness of differential stacks?

The answer is no. Claim: If $\mathfrak{DiffSt}$ were cocomplete, it would be reflective in $St\left(Mfd\right).$ Proof: Let $i:Mfd \hookrightarrow \mathfrak{DiffSt}$ be the full and faithful inclus …
David Carchedi's user avatar
4 votes
Accepted

Vector fields on a simplicial manifold.

How about this? Apply the tangent functor $T$ to $M_\bullet$ to get a new simplicial manifold $TM_\bullet,$ that is take the composite $$\Delta^{op} \stackrel{M_\bullet}{\longrightarrow} Mfd \stackre …
David Carchedi's user avatar
7 votes
1 answer
1k views

When does a submersion have connected fibers?

Can we characterize when a submersion $F:M \to N$ between two smooth manifolds has connected fibers? If this is too hard, what are some sufficient conditions?
David Carchedi's user avatar
6 votes
3 answers
821 views

Two notions of tangent vector for a Fréchet manifold

Let $X$ be a Frechet or Banach manifold. We can define tangent vectors by equivalence classes of smooth curves. But, we could also define them as derivations of germs of smooth functions. Do these two …
David Carchedi's user avatar
2 votes
0 answers
203 views

Faithful actions of finite groups on topological spaces

Suppose that $G$ is a finite group acting faithfully on a topological space $X$. In the smooth setting, one can deduce that for each $x$ in $M$, the induced map $$G_x \to Diff_x\left(M\right)$$ from t …
David Carchedi's user avatar
14 votes
2 answers
1k views

Are all manifolds affine?

There is a classical result which says that the assignment $$M \mapsto C^{\infty}\left(M\right)$$ is an embedding of the category of (paracompact Hausdorff) smooth manifolds into the opposite category …
David Carchedi's user avatar
9 votes
Accepted

Stacks over diffeologies

I will show that stacks over diffeological spaces are "the same" (in the sense of equivalence of 2-categories) as ordinary stacks on manifolds. The Grothendieck pre-topology in question is the Grothe …
David Carchedi's user avatar
15 votes
1 answer
2k views

When does a leaf space admit a (non-Hausdorff) manifold structure?

If $f:M \to N$ is a submersion with connected fibers, then the fibers of $f$ foliate $M$. This is called a simple foliation of $M$ and the leaf space can be identified with $N$. Suppose that a foliati …
David Carchedi's user avatar

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